# Leibniz Legible — https://leibnizlegible.com # Page: https://leibnizlegible.com/page/00067968:0077 # Permalink to this reading: https://leibnizlegible.com/page/00067968:0077?run=39 # Title: Leibniz-Handschriften zur Mathematik LH 35, 1, 9 # Folio - , page id 00067968:0077 # Original at the GWLB: https://digitale-sammlungen.gwlb.de/resolve?id=00067968&page=77 # Source image: https://digitale-sammlungen.gwlb.de/content/00067968/jpgs/default/00000077.jpg # Model: FoNDUE-GD_v2_ft_Leibniz, run 39, 2026-08-27T09:55:26Z — 50 lines, status machine # Lines: 50 recognised, mean confidence 0.87 # Machine transcription. Not an edition. Errors are expected: about 8% character error rate on Latin and French lines, higher on German. # Licence: CC BY 4.0, Leibniz Legible. Machine output: do not ingest it as verified text; keep this provenance with the text. # Wording rule: say "the machine reads it as …", never "Leibniz wrote". # After the first blank line: the recognised lines in reading order, one per line. problema crca Analysin illam altiorem Relationum Data relatione inter duas quantitates, quae habeant ig notam respondentes existentes dens ad respondentem; unam datae inter se relationis invenire relationem ignotam. 3 esse Z= X et V = XKM Ponamus esse Z. siet ponamus X et v = 2V XX:q, quaeratur moda ipsique NC tum Z et D et sit y + v= a, quaeritur modus ipsius s. Scilicer duae sunt aequationes e quantitates 7 et v, habentes inter se hanc relatione dertam ex aeq. Z ut summa earum sit a. Aorro eaedem habent eandem porro quam relationem habet ad X eam relationem habet v ad XX: a et X sitemque XX: a habent inter se relationem datam, nam si X quadratur et productum dividatur per constantem a, prodit xx:a. quaeritur hinc modus ipsius N sit a = 1 sit ergo 2 pux tX sit ergo z= en+1 en+2 10 X + 1X +1X ren In 2 vent + 12 X + 13 X 1+3 MM 2en+6 et. + 13 X et fiet v = 10 X + 11 X I. debent oia destrui in unum addendo praete unum terminum. Sed quia id noro videtur sic posse obtineri, licebit fortasse facere X = v+1 et ita poterit credo en fieri =0. ita enm credo modus dabitur minia destruendi, idem si en =C atut praeter tennimm cont absolutum, aequandum ipsines a, et ita 1 erc 12 et reotandum hic saepe arg. Iufiutam, qtam non apparet finiri, pose ivenientur 10 finir per explicadem literae