# Leibniz Legible — https://leibnizlegible.com # Page: https://leibnizlegible.com/page/00067976:0065 # Permalink to this reading: https://leibnizlegible.com/page/00067976:0065?run=39 # Title: Leibniz-Handschriften zur Mathematik LH 35, 1, 14 # Folio 33r, page id 00067976:0065 # Original at the GWLB: https://digitale-sammlungen.gwlb.de/resolve?id=00067976&page=65 # Source image: https://digitale-sammlungen.gwlb.de/content/00067976/jpgs/default/00000065.jpg # Model: FoNDUE-GD_v2_ft_Leibniz, run 39, 2026-08-27T09:55:26Z — 30 lines, status machine # Lines: 30 recognised, mean confidence 0.96 # Machine transcription. Not an edition. Errors are expected: about 8% character error rate on Latin and French lines, higher on German. # Licence: CC BY 4.0, Leibniz Legible. Machine output: do not ingest it as verified text; keep this provenance with the text. # Wording rule: say "the machine reads it as …", never "Leibniz wrote". # After the first blank line: the recognised lines in reading order, one per line. de lire vo y ay trouve Lan si B est in L + M + N). et quicquid est in B vocetur Y. eritqu. Y in L vel M vel N. Alioqui Nullum Y erit in L Cartesiens toudhant onse il un sçavant si 4 est in AB+ B et non est in A nec in B 6be D. C. Mais te donte es avouće par les ceux qui sont Geometres e et se reduit ve cen est qu’un principe aires, qui regarde imprimes en temps de mande, ninus je ne cendent generalement avois propose il ne puida les deux assit pas, egaux. cotume si en ex que combiem de temps est pas appercu, que bbe ne poterit A resolvi im resolvi in L+ M ∞ dans mon objection