# Leibniz Legible — https://leibnizlegible.com # Page: https://leibnizlegible.com/page/00067993:0082 # Permalink to this reading: https://leibnizlegible.com/page/00067993:0082?run=39 # Title: Leibniz-Handschriften zur Mathematik LH 35, 2, 1 # Folio 41v, page id 00067993:0082 # Scan: One image of two folio pages side by side, registered by the library under both labels (also fol. 42r); this page is its left half. # Original at the GWLB: https://digitale-sammlungen.gwlb.de/resolve?id=00067993&page=82 # Source image: https://digitale-sammlungen.gwlb.de/content/00067993/jpgs/default/00000082.jpg # Model: FoNDUE-GD_v2_ft_Leibniz, run 39, 2026-08-27T09:55:26Z — 85 lines, status machine # Lines: 85 recognised, mean confidence 0.85 # Machine transcription. Not an edition. Errors are expected: about 8% character error rate on Latin and French lines, higher on German. # Licence: CC BY 4.0, Leibniz Legible. Machine output: do not ingest it as verified text; keep this provenance with the text. # Wording rule: say "the machine reads it as …", never "Leibniz wrote". # After the first blank line: the recognised lines in reading order, one per line. supplendum adhuc foret quomodo, sinus et tagentes anificiales possint, habem ex arcubus et contra sit radius arcu a Est autem tangens A sitsisimus versus X. arcus d aadus hariusm (fit sdx: Y2X -XX = a sivus complementi 1 = X = C et bujus relil munda et logarithuu sinus compl. est sdx: 1- X = _PZ fit d = ex. inX et da = dx: S2x -XX fie 1Z. da = 1-X. T2X-XX son - c. Sin ee sine Colligamus plurinia in unum. AC Radius 1, arcus a sio vexsus sirus versus X n omple sinus complinentur ec fouenti ts vel AM secansc rectus Y. et secans e ATlangens F. F tangens complimenti B E langen arcus dimidii d sinus arcus dimidii duplus seu Morda areus dati (egius duplum AH) sinus artificialis sinus complementi arificialis e, langens roctu cmo E = 1. Y C = 1 -X Y= Six -X = - cc. C C: 1: : 1: C. go C = 1: c artificialis _ t: Y: : 1: C. seu t = r: C D Ergo O = C: Y et pronde +D = 1 X: Y:: d: 1 (triangula enim CAF et LBA similia sunt) a: seu d = x: 1 et a = N: Y, et CN dmi sinus coplementi arcus dimidius est est dimirus ipsius EL, chordae areus quae dato AL ad semicirculum deest CYda = X quia deXIr = aX. FEXXX fit D2 = R: 2 X. seu 2d - Xd = x seu X = 2 d: 14 9 arus a = s, dx: (1x - x 3 = (1X, IX V xc dx: drc: r: c. Ergo ex- d de der:c D- dG: AiE est anter Y = iur ergo dy = = tr et dr- . Y = dx. s ex XX sa: d P = dx idr:: t: 1 seu da = + dJ jam a = (_t: 1FF. ergo da = at 1IF F erjo d P = dt: + + +5 e P = s. vtrir 51 = P - Z X log. da = log. X - _ 7 da = + dP. + = da: dP. Ergo dt = _ d P ida = da ddB, : d pr = a. 1+ aa ide E d Sd A dr = x et d seu dP ada = da adp-= a dp + da et ponendu di p =0 sit dP + Ita sed par jure sit d2. sed pari modo habetur larus relatio inter sim consinum artificialem, et arcum complementalem Q- a = (a) et quia d() = = da et et desa) = ada ergo fiet d B dea + da du da dd B = a d B Z d 3 - a d X + da d 1 t da + la F = dt fit dda + dda t + 2da t dt = ddt unde fit = dt: a - 1 = ddt - dda = 2dat dt: dda adeoque fib dt dda = a dda = a ddt = dda a) - 2 + a da dt si jam dda =0, fit ddt: 2 + dt = da. Ergo 25 +da = log. dt Yda = X dad t rdda + da dr = dx et dx = drt. Erg, r EtB de = d. V 2x. XX Errdi potius da 1d P = + dB: la = C: Y = B. seu dP: da = +. Ergo targens ad Ergo summa tangentium ad arcum dat sinum artificialem ita habemus pelationem inter sinum artificialem et arcum seu mod inveniendi sinum artificialem rati arcus per seriem (2: - Xx = - 11 1 4X x 1: i X + 1. 14 X. Ergo s+C: = +C = log _ 1=Z Dlog. 1+ C. seu log 1= C 0 1+XC seu loganshmus ralinis in qua ordinata (ecat diametrum sid - ∞0 1. 1 X + seu log. 1. XX et sex:, xe = log. si sulgnes est, simus artifficialis posito acesse sinumiversum Sitaque sdx: CC, hibsis ec at invemre arcum dP de 1i x. Vivennus an hinc ex sim jam ex da texux. Ergo dP. da V2x XC : 1 XX = da (dr: D. ergo dP = dr: - Y = dr. C ergo dd T = P. Ergo ddq f + dadt = aqate t pa etide in cot B= sax. 1t da = dx: Y. Ergo poiteret da diidere per t, at haberetar 1F 8 sode: C sin dat = 0. fit u -2tda = log dt: 1+ +2 Ergo tda = log 11. et quin de cgnslans (da= loganhinus) posit anthmericae fi =2t da = loy. da et qu’est cantis ergi pronessionis da o secans arrificalis