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# Title: Leibniz-Handschriften zur Mathematik LH 35, 2, 1
# Folio 255v, page id 00067993:0512
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Rectangili KQ. momentum ita invesigare facile est, data recta H P. es euin HB S HR era ticessigada est ergo ante omna
Ip XP. quod ita fiet: DP. ut
et BGF similia eri DX
E DX =, ot
FG
DK. Ergo DK =  BK FG vel quia BK nusus dif resolvenda in FB. Rrevius erit
F5F - 60G
BG.
oc Ex 1X. 190 arG. b. E(1x ig = a fqX
eFB
Lin
C F, a FB, dehadum reliquit XP.
in quam rectam DX KP. dicendim quadratum dimidium rectae XB. Est autem recta KB yF. ego XB = y2
n
sice f - 1 -  s  XXF et qu fL. Lst ru (A  pu 155 pun 1(0)  f mes)
g
9
Sue
fiet (KB = m - coX + nX. ducendum in KP. quod cum sit radix sarda, ipsum KB. tursus quadrandum est,
K8.
fiet m- cx + nX Jsive r 2 max = 2 comX  An X = ZconX + c0X. ducendum primum in y. et
n = cox + nX
m
a produdi demendum idem ductum padice quadrata; adimenda est radio quadrata
coxp ana +CX+) esusdem KB, ducti in DK.  Rosidii dimidum erit Momentum quaesitum.
niX
+nnX LonX3
oxa trinX  d + m 2 porro quia in caeteris omnibus impl trrui componentibus implicitum est X. demto  t.
.tat
ideo reliquis sequestialis, cogitemus tantum M AM duci in y.  sea in f 2. e.
CA ed fiet an f n i (0) cunque reliquis omnibus terminis, sane quam plrimis implictur X. ea omnia simiul appella
de mmodu binus 26. Eritque XB KD in FB. = 0 +
Et quia idem KB ducendum in D,. manifi.
cn stum est, tatum nihil hic oriturum quod non incognito affectum sit, ob dvitorem FB. incognito  affectum, ets
 C
enim ex parte tantum, non potest tamen dividie per partos divitais. ideo KB DR Fieri tamen
mpotest ut ab eo liberetur dum scilice opposita aequationis per divisorem, illum multiplicatur, deo seques
eg is caeteris ipsius B KB terminis in DX. ductis, quae simust cogitemus facert. W quia ipsa
10
scilicet ab inognito liberari non possunt s cogitomus nunc a M indig- a fgX fiet: I ig-
FB
M 1915 1 a f9X n. sed quia posterius a fgxm: ab imognito illiberabile est, ideo pominemus ipsum V
F611 LFBC3
fretus
2 FBC3
19 0 42, = mig + v  o3 = momento Rectanguli XG.
pollimus hoc libre spesidere, e smplicite numentum Sed possum disinpliciter, momenture totius rectanguli
BK H F ipire multip licando quadratum KB in FB = ob 40  96 ergo 2o aealim .dB,
simi
21 2 d,5
Nun et momentum Ii ABZ. AGB. Nimirum sta omnium AQ et paralletm est Trimegulia ductum ii
XB. et praeterea appliculer li ipsi Aq. parallela dudae quadiata dimidia. Jam AQ = a - 9CAd. Bd)
B
1
Ergo A2 = aBk - gBk lam BK. = FBf. Ego Aq - 2 FB- gsEB Hdui Q Aq erit as FB g FB
est
 p ca per a f, vocemus (p)  uliqua per endem
vocemus: (G.) habemus. P + P2 eodem modo cum f92 e 
A
s
+3
94
ergo A9 =  p + 9 q + Yp hoc ducnue in HC. A in FB. ig - a f9F
fit Q H ipsius Aq. menge Ag 2. seu P + 4 - 2 p q et c. F. etC. hocu ducat n FB. ducatur
3FB
ego tantum in f= l etc. sed hoc appellemus a reliqua neglecta omnia, exd ductu Gooriunda: (65 6) habemus.
A8+ F5
Idem A3 ig dubit multiplicet,
EFB
in ea tantum P = 4, d pietqus (24). reliqua in ner ig  = (5. 3) denique A9 in a7 GX = (53
(3FB
3FB
Si
YDFB2C
fiet :  + 5 p F AQ in DK. Ergo AQ in KC = sa + 8 - p  +  +
a2a bf. 2a6 b
Alromento Trianguli AQB. q
5d
t ia  istomentum jam quadilinei APHFg. quaerendom est.
hFB
ac primum momentum totius AFAB semisegmenti, id est E AP. ductum in a demto cubo H P3 Ae primum
B AC est.  BK + A2, _. seu BK + Ag = 2 AQ Bk. Ut quidm A2F, a f fB. 19fFB, et BK L
AFD F. Ergo A3 BK= FB C a gf  f. jam F = f. ;2
v
s
P2g
6f = ()2) et reliqua mnia emit (H2) ergo AQBK = V  N Jan
L AB = BK + A2 4 - 2  = = n. = m cox +(nX + P  s 4. F P su. n + p. g rna. enipu
Ego 1 AP= S - X in a, erit ad= qu. Munc opus ut in vestigemus m ipsiu AP.
62
um HC= _ HD) = DPC, (FB) Ergo HP = a = FB. cubus de a- f B est a   FB + 2 a FB  F B. 3, otrdau
seu a = 14 D = r + x 4 51 32 + D E90  ad  an = a + YqB + 16 s 45
+ 2 F ~ Momentum est semitenen   et t Pa   cuo aliter ptus cntralum
Jurestindus et onenuent, semmpegment ei H Reprimi (FI BK. HP. ducatur in H ers  at
sed salso devminitio pss H B, nempe a - YB. et humc eviorem jam supra erravim nec satis patientiie est, ad ista relene
a - ab + b=
isradieh
0
eu