# Leibniz Legible — https://leibnizlegible.com # Page: https://leibnizlegible.com/page/00068043:0015 # Permalink to this reading: https://leibnizlegible.com/page/00068043:0015?run=73 # Title: Leibniz-Handschriften zur Mathematik LH 35, 5, 25 # Folio 8r, page id 00068043:0015 # Original at the GWLB: https://digitale-sammlungen.gwlb.de/resolve?id=00068043&page=15 # Source image: https://digitale-sammlungen.gwlb.de/content/00068043/jpgs/default/00000015.jpg # Model: FoNDUE-GD_v2_ft_Leibniz, run 73, 2026-08-27T15:28:38Z — 39 lines, status machine # Lines: 39 recognised, mean confidence 0.89 # Machine transcription. Not an edition. Errors are expected: about 8% character error rate on Latin and French lines, higher on German. # Licence: CC BY 4.0, Leibniz Legible. Machine output: do not ingest it as verified text; keep this provenance with the text. # Wording rule: say "the machine reads it as …", never "Leibniz wrote". # After the first blank line: the recognised lines in reading order, one per line. datis punctis C et D. et recta indefinita AB Ducere CED ita, ut sit CE. C + ED. M omniam possibilium minimum, seu minus quam foret sumto E alio quocunque sit ntu Ex punctis datis C. D. dicantur ad rectam perpendiculares CF et DG Dabitur FG aequ. f. et CF, c. et Gdd sit FE, X eut GC aequ f -x. et CE aequ XX + CC. Et DErq. H xF dsebet C CC+xX +M ff. 15X +Xx + dd aequ y esse omnumm possibilium minimum sit Lunitates, et utde nosit sit nitas L. sit m. seu eat erit CH aequ. l LCCFAY sit CH ad eE ut L (sumta in CE si opus producta) ad CE ut l ad uutatem et ruisus DK (sumta in DE si opus producta) ad DE ut M ad unitatem. patet rectom et per H et K ducantur KN, K P ipsi AB parallelae, patet quamvis rectam CH ex dato puncto C. ad Hd rectam HN ductam fore sccta et quamvis Dk for + m rf. 2fX + X+Yd CE sit e. quaeritur R eAqu CH erit CH: CE:: (Q: CF seu C debet autem esse CH aequ. l. CE: +g Ergo fiet: l. CE: f: CE :: C9; c seu l: f:: C2: c. sit ergo C9 c: f similiter DR erit Md: f ergo erunt CH. DK ipsis rectangulis L in CE et M in DE proportionales quaeritur ergo quomodo assumendam punctum ut fiant rectae CH+ DK omnium minimae sec +XX + m Vf - 2fX +XX + dd aequ. y. Ergo pro manima 2Ix e-a2mf +2mX aequ. c. Ergo m Scc+X et faciendo DE aequ. CE. erit - l. X aequ m. f-X Ergo l. X. DE aequ n. f - X. CE idem vicissim demonstratur s e xx sit aqu qque fiet: Xxaeqo 2Z. CC et X aequ( ZZ cc. et fier 1Z +. moss- 2f s cc +4 cc +d ∞q s demonstratio linearis non adeo facilis