# Leibniz Legible — https://leibnizlegible.com # Page: https://leibnizlegible.com/page/00068124:0227 # Permalink to this reading: https://leibnizlegible.com/page/00068124:0227?run=73 # Title: Leibniz-Handschriften zur Mathematik LH 35, 8, 30 # Folio 114r, page id 00068124:0227 # Original at the GWLB: https://digitale-sammlungen.gwlb.de/resolve?id=00068124&page=227 # Source image: https://digitale-sammlungen.gwlb.de/content/00068124/jpgs/default/00000227.jpg # Model: FoNDUE-GD_v2_ft_Leibniz, run 73, 2026-08-27T15:28:38Z — 33 lines, status machine # Lines: 33 recognised, mean confidence 0.80 # Machine transcription. Not an edition. Errors are expected: about 8% character error rate on Latin and French lines, higher on German. # Licence: CC BY 4.0, Leibniz Legible. Machine output: do not ingest it as verified text; keep this provenance with the text. # Wording rule: say "the machine reads it as …", never "Leibniz wrote". # After the first blank line: the recognised lines in reading order, one per line. SUse 27 (1mo) aq+o+ ab = S sit 2do) = C t Ex + Sux et Cno) ( g+ hx + L X. et f PagsBs agcc + 29ceX + 2gC f XX + que n + 2get X + 9st X se congendium sit (610) abi d = ab gg + vg h X + 2bgK xX 4 aa ae + bhh XX + 2bhKX + bKK p 2ito) aa a3 C_ = m + 4 mnX +6 mmuxs + 4 mr X + 1t qet A = Bleaqc e + abgh B = agef + abhk C = agee + abhih. + 2a9cf + 2abgk D = agce + abgsg C = a 95f + abkK Hinc ex 5 et 6 fit (mo) Hinc ex pet 6 fit (ymo). A = 2mn et B = 2 mn, et ) C = 5. ma et D = m e E- n ) et ED6 m n AM = 4 me n. Ergo ACd = 6AA seu 2CD - 3AA (8V0) 2Cd = 3AA. et similiter B (9n0) 2 CE = 3BB _ denique AB (10mo) AB = 4dE Ex 7 facile habetur m et n, nam mn H (C: 6). Et ( + B): 2H(C: 6) mm+nn. itaque per A, B, c fale habentur plane tam m, quam n Nunc in a49. 8, 9, 10 substituendo valorem ex 6, habebimus fres aequationes carentes ipsis m et n, nempe ex aeq. ( fiet (130) 3 () (gef. + bhiX) = 2, 9fft bNk, qeerbut 29cf + gee + 2bgk + bhk compendii causa et ex 8firt 141) 3 1 (gect bhgs) = 29 cc + bgg, 29cf + gee + 2b9k +bth et exiohuilis to) Pqee + bfg, gef +bhK = 4, qec + bgg, 4ff +bLK. vel B vel A sit . sit (166) O= qef +bhk et D(= gec +bhg et 8 vet E = 4sf +bKK, et d vel E = 9f5 +bHK et Q vel D = 9cc + bgg. et 4 = gee + bhh et T = qcf + bgk sit C = 2 + 2h et ex aegq. 13, 14, 15 frent regu C92a ett M X aX