# Leibniz Legible — https://leibnizlegible.com # Page: https://leibnizlegible.com/page/00068182:0002 # Permalink to this reading: https://leibnizlegible.com/page/00068182:0002?run=74 # Title: Leibniz-Handschriften zur Mathematik LH 35, 11, 9 # Folio 1v, page id 00068182:0002 # Original at the GWLB: https://digitale-sammlungen.gwlb.de/resolve?id=00068182&page=2 # Source image: https://digitale-sammlungen.gwlb.de/content/00068182/jpgs/default/00000002.jpg # Model: FoNDUE-GD_v2_ft_Leibniz, run 74, 2026-09-06T16:05:13Z — 62 lines, status machine # Lines: 62 recognised, mean confidence 0.88 # Machine transcription. Not an edition. Errors are expected: about 8% character error rate on Latin and French lines, higher on German. # Licence: CC BY 4.0, Leibniz Legible. Machine output: do not ingest it as verified text; keep this provenance with the text. # Wording rule: say "the machine reads it as …", never "Leibniz wrote". # After the first blank line: the recognised lines in reading order, one per line. lecare rectam in extrema et media ratione Analysis indeque deductae tam constructio Linearis sit recta ule canda quam appropinquatio numerica A quaeritur punctum sectionis B, ita ut sit m AC ad majorem BC, ut BC ad minus AB BC erit a - b et fint ab = aa + bb -2ab seu bb - 3 ab + 3 aa = 2 aa - aa = 5 aa, seu b - 3 a = s5 eritque AC sit a AB sit b b = 2a - 4 15 seu b = (1+ 2) a - a H1 + 4) Hinc constructio erit talis AB Rectada data AC addantur tres dimidiae cd, ab eadem detrahatur quarta pars AE ad datul dimidia CD, et rursus tota DE asqualis AC et ab eadem AC detrahatur quarta pars AF, Tum super FE descri. BA. AC = CBqu bame seuncirculus FGE cui ex D educta perpendicularis occurrat in G ex jam ex D ad partes A sumatur DB aequa lis ipsi DG, eritque erectem B B punctum quaesitum demonstratur ita: Nam si AC sit a erit AD ex constructione AD. (1+ 2) a, a qua si detrahas AF a restat Fd (1+ ) a currus dE est a ergo DG med. prop. inter Fd et dE, erit a ((1+ 2), cui si aequalis sumatur dB tunc erit AB, _ seu AD - DB, erit (+ 2) a - a (+ 4) jam quia AB seu b est (1+ ) a = a (1+ 4) =a + a ( = 4 comprobationes duas 1 utique fiet Hini comprobationes AB = a + = a - a V1+ 4 Cen Ninc prima BC = - a + a. 11+ Z Ergo AB + BC = a X segunda AB in B AC = aa (1+ =) = aa (1+ secun B C quadrat = 4 aa + 1+ ) ac s- aa Y(1+ da seu aa (it L)= aa Y (1 Ergo AB in AC = BC quadrat 15 = 24 236062 + etc 1000000 Ergo AB = L a = 118033; + et a- 1000000 481966 + et 1000000 seu AB ad AC ut 481966 + ek ad 1000000 2 500000 118034 481906 Figura paginae versae Huc transferatur tre e 14) = 2 1