# Leibniz Legible — https://leibnizlegible.com # Page: https://leibnizlegible.com/page/00068188:0001 # Permalink to this reading: https://leibnizlegible.com/page/00068188:0001?run=74 # Title: Leibniz-Handschriften zur Mathematik LH 35, 11, 15 # Folio 1r, page id 00068188:0001 # Original at the GWLB: https://digitale-sammlungen.gwlb.de/resolve?id=00068188&page=1 # Source image: https://digitale-sammlungen.gwlb.de/content/00068188/jpgs/default/00000001.jpg # Model: FoNDUE-GD_v2_ft_Leibniz, run 74, 2026-09-06T16:05:13Z — 40 lines, status machine # Lines: 40 recognised, mean confidence 0.92 # Machine transcription. Not an edition. Errors are expected: about 8% character error rate on Latin and French lines, higher on German. # Licence: CC BY 4.0, Leibniz Legible. Machine output: do not ingest it as verified text; keep this provenance with the text. # Wording rule: say "the machine reads it as …", never "Leibniz wrote". # After the first blank line: the recognised lines in reading order, one per line. Mathem THEOREMA PYTHAGORICUM Empirice demonstratum circa rectum Trianguli rectanguli duorum Laterum quadrata aequantur Quadrato Hypotenusae ut horumlatera cd, BG se secent in L Ecthesis: Esto Triangulum rectangulum ABC, dujus angulus rectus B. dico quadrata acela lateris AB, et lateris CB simul aequari quad rato hypotenusae AC. ppapiratio: Super AC erigctur quadratum ACdE, et super CB quadratum BCFGP. Ex E opposito prua mon- strata ipsi C agatur in AB perpendicularis EF. Cum et super ea erigatur quadratum EFCH Denique ipsiDL sireatur in AL aequalis AM et ex M ad partes 9 latuseai d geat in ABs agatur porpendicularis MN Et aequatur ipsi AB. Nam ang. EAF + ang. FAC = rect. et ang. EAF + ang. AEF = rect ergo ang. FAC = ang. AEF. Ergo triangula EFA et ABC habent eosdem angulos, et agum loppotenu jam hypotenusas habent aequales AC et AE, ergo triangula sunt congrua inter sE, seu et EF = ipsi AB. Cemmn etd esi conguua elet ect itaque ostendendum, quadratum ACDE aequari quadratis BCFG et EFGH simul, cum quadratum ipsi ab EFGH aequatur quadrato ab AB sad pri oetendemus sed prius ostendemus HG transire per D. Nam cum angulus DEH sit aequalis angulo AEF, et DE, EH, ipsic respective) AE, EF, congruent DEH et AEF, ergo HD ipsi FA, et angulus HFE, angulus ad F ipsi angulo HD ergo et Hic est rectas, ergo, sed angulus DE GHE itidem est rectus ex constructione Orgo Hd et HG cadunt in directum, cumque D et G sint ad easdem partes et Hd minor quam HG, itaque HG transit per d. destali Ceta Demonstralio onstratio Eminirica EFGH catur aqu’aece DEFL + EHD + DBB edL t DEFL aequ ACDE aequ aqu + EFA + ANM aqu edtm FGL CBL