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# Title: Leibniz-Handschriften zur Mathematik LH 35, 12, 1
# Folio 59r, page id 00068194:0117
# Original at the GWLB: https://digitale-sammlungen.gwlb.de/resolve?id=00068194&page=117
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# Model: FoNDUE-GD_v2_ft_Leibniz, run 74, 2026-09-06T16:05:13Z — 33 lines, status machine
# Lines: 33 recognised, mean confidence 0.90
# Machine transcription. Not an edition. Errors are expected: about 8% character error rate on Latin and French lines, higher on German.
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# After the first blank line: the recognised lines in reading order, one per line.

  Cdud qae libet
Continens est unum in quo sunt multa. sit continus , aeenltie  A et B,
et quid est in L, voceiu L, eri tunc et A sont in B si A sit L, et B sit L, etc
et omne L sit in L,  erit L continens, A, vero et B erunt contenta
sint in L, duo L nemipes A et B nec possit A assum in aliquo M existente inL
Rom
onetu
quin possit etiam B assumi in aliquo tali
ut M et N habe ant aliquid commune,
en qu s fis positis dico L esse continuum et omne Pe sit L. liciam autem
Si omne M sit L, et omne N sit L, F omne L sit M vel N,  Erit L contri
et M, N erunt contenta consufsicientia, vel erunt constituenti integrantia
Dua continur, constituentia consufficientia habent aliquid commune
sit consinuum L, erus duo constituertia consufficientia, sint  ut 
rvitri sc ponatur  et  nihil habere commune, in A a assumiatur utcunque
Ai et B in B  A non est in  B nec B in  alioqui B  et  haberent ari quid:
commune controa nyp. Sed quia tamen A et B sunt in L continuo, aportet dami
posse A in aliqua , et B in aliquo N, sic ut Met N habeant aliquid commune
A Ipsum commune MN, non cadit ex _ et B simul alioqoidum hyarent aliquid ommane contia hiy
 ssis smsi o titum k, M2, AK, _2 + H aon = non H, N non 9 uon B
set issicito ti ibirem e proestate continnum sicdefinin,
Continuum est cujus duo quaevis constituentia integrantia habent aliquid
Commune sit continuum L et integrantia ejus sint n et N, dabitur aliquid
MN, et vicissim si duo quavis M et N intogranti E h. veant aliquid commune,
Hina non possunt afsuolari pun duo  L, nemp vedat A et B, quin en smto B.
inprontinuo
plum L continuum erit
si in continuodentur A et B, et e quidem in M, duo poterit reperiri N
continuum ipsi M, in quo sit B. tale  continuum N, erit quod supererit
in  in  in M
si ab L abscindas M, et quicquid praeterea volueris, quod neque M neque B
continu at
idm N