# Leibniz Legible — https://leibnizlegible.com # Page: https://leibnizlegible.com/page/00068194:0135 # Permalink to this reading: https://leibnizlegible.com/page/00068194:0135?run=74 # Title: Leibniz-Handschriften zur Mathematik LH 35, 12, 1 # Folio 68r, page id 00068194:0135 # Original at the GWLB: https://digitale-sammlungen.gwlb.de/resolve?id=00068194&page=135 # Source image: https://digitale-sammlungen.gwlb.de/content/00068194/jpgs/default/00000135.jpg # Model: FoNDUE-GD_v2_ft_Leibniz, run 74, 2026-09-06T16:05:13Z — 22 lines, status machine # Lines: 22 recognised, mean confidence 0.93 # Machine transcription. Not an edition. Errors are expected: about 8% character error rate on Latin and French lines, higher on German. # Licence: CC BY 4.0, Leibniz Legible. Machine output: do not ingest it as verified text; keep this provenance with the text. # Wording rule: say "the machine reads it as …", never "Leibniz wrote". # After the first blank line: the recognised lines in reading order, one per line. C (E est in AC DE est in AB. (3AB = AD. (4 AD + DC = AC () AE+ EC ∞ Aesu AE + EB ∞ (per 2) (() Ostendendum est ese AE + ED ∞ AD. C esse inAD. seu fugamus AE+ ED 1 AD. Ergo AE+ ED = AB Ergo AE, + EB = AE + EB AD + D(~ AC) ∞ AE + EC. pursus AE+ EB∞ Ergo AE ∞ AD+ DC, EC Rursus AE∞ AB. EB Ergo AD + DC E∞ AB BE AB - DE ∞ EC - CD. Ergo AD - AE - D ∞ A EC - CD -DE Rursus AB = AD. demonstr. AB∞ AD. _AF + EC ∞ AC AE + EB∞ AB ADLDCOAC AD = AB. ostendendum est esse AE + ED ∞ AB AD= AE + EB. Hoc ostendetur, siostensum sit AE et ED non habere partem communem. Nam AE et EB non habent partem communem, AE et EC non habent partem communem AD et nnon habent partem com sed AD et