# Leibniz Legible — https://leibnizlegible.com # Page: https://leibnizlegible.com/page/00068194:0140 # Permalink to this reading: https://leibnizlegible.com/page/00068194:0140?run=74 # Title: Leibniz-Handschriften zur Mathematik LH 35, 12, 1 # Folio 70v, page id 00068194:0140 # Scan: The same scan as fol. 69r (00068194:0137), where its text is given. # Original at the GWLB: https://digitale-sammlungen.gwlb.de/resolve?id=00068194&page=140 # Source image: https://digitale-sammlungen.gwlb.de/content/00068194/jpgs/default/00000140.jpg # Model: FoNDUE-GD_v2_ft_Leibniz, run 74, 2026-09-06T16:05:13Z — 40 lines, status machine # Lines: 40 recognised, mean confidence 0.91 # Machine transcription. Not an edition. Errors are expected: about 8% character error rate on Latin and French lines, higher on German. # Licence: CC BY 4.0, Leibniz Legible. Machine output: do not ingest it as verified text; keep this provenance with the text. # Wording rule: say "the machine reads it as …", never "Leibniz wrote". # After the first blank line: the recognised lines in reading order, one per line. Prop. 1. lib. 1mi Euclidis. super data recta linea terminata AB treamgusum aequilatiam pat nrmnleni etbo AB descr N et N YB AB. Sit B et AM = AB. Et aros in sit R exit aliquod _M ∞ aliq. R per Lemma sequens extra quod non erit Y. (per Lemma sequens.) id sit C. junge AC (= AM = AB) et BC(= BR = BA ergo AC = AB = BC. Quod erat Fac emma siduo circuli MB ex A et A habeant mutuo centrum in alterius circumferentia B in M et A in R. eorum circumferentiae M et R sibi occurrent alicubi in C et tranfeuntem. Iisdem pod duae sunt in quo omnia sunt sit partes L circulum et oun centro ex centro A, et N extrupirculum exit ALmon major AB et ANo minor quod niha it est ALB AB. ANH AB jam jam at qu. R est L (nam qu. R est A quia BA = BA. n et A est L. quia AAB AB) et qu. A est A (quod sic ostendo: producatur AB in D ut sit BA seu AD dupla AB. erit D erit R et Derit N. Ergo qu R est N) Ergo qu R est AE per axioma de continuis, qu. R est M. Zu. E, D. Axioma de continuis si ejusdem continui D duae sint partes cointegra L et N, sitque alterius continuim N parki aliud continuumR tam intra Z quam intra N erit aliquod ejus punctum in M. communi termino ipsorum L et N. pot est demonstrari ex definition utu ce = et BR = BA circumferentiae s euru