# Leibniz Legible — https://leibnizlegible.com # Page: https://leibnizlegible.com/page/00068194:0349 # Permalink to this reading: https://leibnizlegible.com/page/00068194:0349?run=74 # Title: Leibniz-Handschriften zur Mathematik LH 35, 12, 1 # Folio 175r, page id 00068194:0349 # Scan: One image of two folio pages side by side, registered by the library under both labels (also fol. 174v); this page is its right half. # Original at the GWLB: https://digitale-sammlungen.gwlb.de/resolve?id=00068194&page=349 # Source image: https://digitale-sammlungen.gwlb.de/content/00068194/jpgs/default/00000349.jpg # Model: FoNDUE-GD_v2_ft_Leibniz, run 74, 2026-09-06T16:05:13Z — 64 lines, status machine # Lines: 64 recognised, mean confidence 0.82 # Machine transcription. Not an edition. Errors are expected: about 8% character error rate on Latin and French lines, higher on German. # Licence: CC BY 4.0, Leibniz Legible. Machine output: do not ingest it as verified text; keep this provenance with the text. # Wording rule: say "the machine reads it as …", never "Leibniz wrote". # After the first blank line: the recognised lines in reading order, one per line. Invenire Hujus problemalis osanna non nisi unum exa porut vid. Dian 690. anver 3 jil 1t14 A eactem Ut Triangulum Rectangulum in numeris, ut summa aboruta id lalentus sit cubus. Tiranguta Latera Trianguli Rectanguli sunt 2ab, 4a - bb aa + bb. Horum cub 32 a Cubi collecti dant 2 14) 162 (17 3ab + a =3 at bb f3a a b b + a (3 a b0+ 3aa b + b = c (3 2 seu 8ab +2a + 2b = C3. sit a= cd et b2 ce et fet sit c aa + bb + d et fiet 8ab u + (2b (a) + 3 ab + 3a b+ + 3 a bd+6a bd + 3abD+ 3aa dd, + le dd + d3 sit c = 2ab + d fiet (8a b) + 2a + 2b = (8a b3+ 12 a bd +6 abdd + d jam aggregatum duorum caborum semper est divisibile sit X3 +13 dividi potest per, XX - xy + yy. Ergo et a + b dividi potest per a- aabb + b+ sed nescro an sic rucremur prastat aequavem reducere (2) problema ad simplius, e nempe sitr a = d et b = e, fiet eab + a 8 de + 2dd + 2 ee , C faciamus eru d c= fd et e c= fe, et d = ge et ReY 8gec +299eC+ 2eC L f3C3 et divisis omnibus per ce, fiet e= 2+ 8g + 2998,: f3 63 110) 63. Ergo tantum dpus est 2 +89+ 24g aequare cubo (5b3 seu) h seu 99 + 4g. = 13. 2- in seu 99 + 49 + 4 = b: 2 + 3 V(II unu uende 9 +2 = Sih + 12. 2 seu fiet 2+ (10) itaque opus est 2+8G + 299 aequare cubo, (f3b seu) et fit99 + 49 +4, ∞2) (1) Dxh - 1 + 4 seu g + 2 = S2t + DE : 2 ergo seu a: B3 4Y t3+ E2 B. 16, :8 Ergo re (74. huc redit ut V4 St+i = 16 sit numerus. Ante omnia ergonh3+ 12 aequetur quadrator in definite seu nm videamus quomodo formemus 12 ex A. H + un + na + n U + tm + mn = 12 I + m 3. m sit latus quadrati a et fret h1) amm (F 12) + ginim seu mmh = 4m + 9 fiat aef. n -2 et m pt2 Ergo ex aequ. N. fie b n_ - 6n + 121 = 8 + 12 = pp p + 4 Unde sit l1ct) +94s Ergo se sed ita oporteret = 12 +89 + 1299.+q aequare quadrato Et ita nihito facilius hoc est pri aeque Isi prastato rec uideamus quid fiat, si redeundo ad aeq. I1 pro g Rbnamus pro9 seu a:6, faciamus r3. et siet. 2 + 8Y3 + 276 = h quia autem habemus unum exemplum 3, 4, 5, fiet tunc a = 2, b = 1, 2 + C = 6 d = 8 C = 1 f = V 6 = 8. AY3 + 4 Error fuit in calculo reassermam