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# Title: Leibniz-Handschriften zur Mathematik LH 35, 12, 1
# Folio 296r, page id 00068194:0591
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problema:
Datae basi Trianguli, uno angulo ad basin, et flano sub duobus lateribus
Dinvepire Trangulum.
tangen
et CF
Esto basis a. jus anguli eati b Caltitudo Tianguli-X erit
 = = a. Ergo DF = ab, ejusque D, a b addatur ad X
DF
recta
N. datu e etiam limeatG.
fiet CD = a b + X ab+ X ergo et a rectam _.
ratio- 8E jam dati  Eg
Porro EF = a = ab ejusque B a = 2 a b + a
cui si addatur X, fiet CE= a - 2ab + ab
ducantur in se invicem CD=  ab  x
et CE = Sa X - 2 a bx + a b + X
datur
fiet S. abx - 2a bx + a b + ab X + a X - 2abX a b X + X 
X
6, X - 2a b 6 A 2a b + 2a b   + ab X- 2ab.7 a6
vel:
sitan
cono datur GE Di ergo et HE,G est = GCFD Ergo datur et AD. ergo datur et Hi
datur et GH. porro HECd = DECF Em GD. DE = CD et DC= HE = Ego-
ee
ergo si p paralleta A, et = DE,  tunc EF mod lEas adet in N, quia 
2. ae solitur
+ X _+ a  - 2abX + aeb X (). A2b X- 2ab X + ab = - 0
-a e
Aequatio data
Eequatio similis
00,000000  vel: C 0 0 0 0 0 0 0 0
d +4 000,000
2aD0, 000
 111000
sabb0
rad 0 0 0 0 0 0
-ac 00 0 0
+47 0 0 0
Si
se
E et  
CDC
ergo CF = CE. Ergo
C CF C5 D
2
datu
10
cda
- 4
e= 6
d= Y
c-
Et posito
a=1. netalis pro lilitu
90 7 b 5
vel 1 0 3 4 5 0 7 89 =- 0 depressam.
vel 10
1
0
3 0 5 g 7 0 9 = 000400080
e
0 4
Vel posito: ac 1. bc 2 c 237
fieti . ...
24 35
seme
vide in plagula
adhaerente, idem
problema bon
e
se solutiu
aequatione
vel. 10
4 1 0 256 =029