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# Title: Leibniz-Handschriften zur Mathematik LH 35, 12, 2
# Folio 37r, page id 00068195:0073
# Scan: One image of two folio pages side by side, registered by the library under both labels (also fol. 36v); this page is its right half.
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# Lines: 50 recognised, mean confidence 0.77
# Machine transcription. Not an edition. Errors are expected: about 8% character error rate on Latin and French lines, higher on German.
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# After the first blank line: the recognised lines in reading order, one per line.

2x ∞ 2f 2 + 3gn + akx +5Cx + bax + s + 1L
+ ca xict +BC9+14ch+15CC + 16CX 417 Cy +n C
yW ∞ 12fy41097-14n9 - BCy - 16 Xy -179y4 n y
+Yx verfa +2392+ rahu t2etr + 26nu +27y + 21 X
= co ∞ 32ct - 33C9 = 34ch - 35 cl - 36c x - 37c) - 3lc
+vy ∞3fy F2gy+ 2ghy 13rly + 2b ry+37yy+ 3l7
110 + 12c4 + 13C9+ 14ch + 150C +16c8+ 17cy L 2fx + 39X
31c =3267 =530g - 34ch - 35cl - 3bca - 37c7 +22fa + 23gu
+ 1 X = 11. 
+ 21 ∞ + 31 y
+ 4ha + 5ex = 124y - 139y = 14hy - 15Cy - 16 a y +6 n
+Edhu + ex + 32fy +339y +3429+35C7 Jny+2620
+ 2727
+ 36~y
+ 17yy ∞0
+ 375y
Endo indieumen dese waerdem nan 2, c0, y en v hubtitucert
in de 7. cequatio, aes d.∞ d+ Y, oste du -cox ∞ ds +1y, oft
Ciener di - xo-dy - 4y 30, sal comen
da 212 t 1 13dg + 14 sg + 15 eg +
deo ∞ nat, +13dg + 1dh + 15 de + 10d + 17 dy + 1d
K cd 50- 12+ = 13ng - 14Xk - 15 n l - 16X n - 1 7 X y - 11 2
dy
∞s D-3 - 2399 - 249R - 259l - 26 ny = 2797 -217
(3 X
MatIEat + 13dg + 14dR + 15dC   - 13gK - 14k r,
 12 f X
=15 ex = erfy - 2397 - 24h7 - 25 Cy = dy - 17 x y - 16 ne n
=2795 + 16dx ∞0.
+ 17 dy - 26x y
21y
En indinumen defcere vaerdent euortituaert in de 10e
cequatia et ∞ +Z, osto ey +ry xevtxo osto zy-ev-vnte
10, lae comen:
2y ∞ 2fy+ 2971 4ky + sey + 62y +797 + ty
eo ∞ - 32cf - 23 cf - 34 ck -350 -36c X - 37 ey -31e
= XV x - 32) - 33Gn - 34hu - 35 Cn -= 36 ~n - 37 7 x - 31 n
+ e
- 32 ct - 33eg - 34 ch - 35 el - 36 en - 37 ey - 32f n - 339r
=31 x + 
= 34h n - 35 Cx + 2fy + 39y + 4Ry+ 5ly + 6ncy,
31 e
-3bna + 7yy 4 y ∞0.
-372 y
Doneu alle cet weeche oii noch Arvec audere cequatieu
Eebden, aer 0c0 - 2c0o +cc ∞ ∞ aa = Y oste  W + 25 2-
= 2cW0 = aa + cc ∞0, en vv -2c0 +cc ∞ aa - 22 oste 22 + 00- 2c
= aa +cc ∞0, in deweltro 300 oy du eonergetel de Waerdem
nay 2. c0. 4 eu 2 subitituereu, Pae iomen.
+ ey x