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# Title: Leibniz-Handschriften zur Mathematik LH 35, 13, 1
# Folio 372v, page id 00068196:0740
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X = 30 V + 31 + 32 + 33 etc.
ex = 1, 30 -172 - 2. 30 - 3. 24 e2t
X = 30 v + 2. 30 3V + 2. 30. 32 + 2. 30. 33 + 2. 3034
+ 31. 31 +2. 31. 32 + 2. 31. 33
+ 32.56
-. 2 38. 34
=2 1. 31 
E P. E2
Xdx = 1
Xdx = 1 2. 30. v 4 1. 2. 30.31 F X 9 2 30. 2
1pr. 3.3
avdx = a
XVAV = 300
130V
3IP
XVAx = 1 230 4. 2. 1031
32
br
-1. 2.30. 31 -2. 23034 - 3. 2
2.31. 32
3
32.32 2. 32. 33
ubi video 30 = 1 et seu 30 + 30 = 0, ubi 30 vel est1 vel est 0. Et quidem pt esse o, si adsit
a
ado
et etiam 31 fiet 0 habeliturque 32, et 33 etc. sed si sit 30 = -1 fi quod necesse.
foret, si abesset t-a, fint -a + 31 -30 quod absurdum, nam fieret a = 0 Ergo t
si in aeq. aadu +Xy du + Xyax + aydx = a X dX  sit X = b Z C V et y- m Zu tiB
nihil to frustra haec agimus.
fint dx 3 b dZ + edo et du - maz + ndv, et fet Xya b bn Zb
i
as maq cxy
nav
aa A3
 xde
  = 4 du Xy Adydx Xy = 
ad sit v - t  b bet  c0v = 2 ay ci, atb = C - cb + Cb sit ergo v = 30 + 31X + 31 X etc
a
  fibt 1. v = 30 =
go 30303 30
quod si jor. pro v sumamus co
+ 3,2 X + 2.31 32.
303
303
+ 3pX
3
et sibaequalio - a du + adx + xdeo =0
 patet co- 40= 41X-42X, eodem
modo haberi ex Y, 40, 41 42, X, a
ut N = 30 =3(X = 32X habetur
ex 30, 31, 32, X, a
et quide 31 et 41 =0 erqu
0
est solum in 40 etc2 in 32. unde
si lollas a per 42, et  inquiras
ex X et gr (uti haberi pb ex X et a)
titues in valore ipsius co per X et q
30
cujus itide datur vator Ecyb suberesset ut inveniretur haec
Pro 32si u 42 substitues 32
curva: adco: coa na + adu 4Xdio =0 ubi jes licebit
explicare coper X, et habetur solutio facilis per seriem infinitar
ana
a ded=
sit lenim X = 50 +G eo + 52 Co +53Cd etc et tt ao x a,
Hik aee
31. 33
en Do
as ryta
X
= 317 X = 31. 32 X - 31, 33 X
12
+ 3D X +3141 31 X
2923
303
+ 313 7
.31. 32
L2. 31132
+4. 34 ero
ara, 
xAdo=
ressix-
M. 51Cd + _ 32Co + L. 33coe
+50 S 52