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# Title: Leibniz-Handschriften zur Mathematik LH 35, 13, 2b
# Folio 27r, page id 00068198:0053
# Scan: The same scan is also registered as fol. 28v; its text is given once, here.
# Original at the GWLB: https://digitale-sammlungen.gwlb.de/resolve?id=00068198&page=53
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# Model: FoNDUE-GD_v2_ft_Leibniz, run 74, 2026-09-06T16:05:13Z — 94 lines, status machine
# Lines: 94 recognised, mean confidence 0.72
# Machine transcription. Not an edition. Errors are expected: about 8% character error rate on Latin and French lines, higher on German.
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# After the first blank line: the recognised lines in reading order, one per line.

seu X = 
W4 
ac +bc0+
neo +Co + p.
v + b0+ 4
mv + nv +p
MDX + nvX + pX = a v + b v + C
vD + nx - b v  = C- pX
mx-aa
IX =aa
VV + nX - B v + nX 2n bX + b +n X - 2nbX + 
mx-aa
T ner2maxta
sin = 2n BX +
amx +4meX ac
+aa
D = 1 -Am.. + anque. = 4a = nXt3 2, nX = 2m axta
et
+4ap.
2, mx - aa
la ... . . . . ..
60.
 an
momanmnam n a mn
2, mx aa
Sit gent. (10 X+ 1X + 12 aeg. gto (0X  2. 1019 + _
Eyt
fit nX +e - 2. 10_yX = . y = 12. seu X =  y= 12
11 = 2. 10. A
et 110210X + uX +12 = . 10X + y = (10yy 10. 12 F 11y (310y
et fiet
( =
iax sta
 + any - 10. 1a
mat
+an: 12
ana -2. 102y + al31I
2 myy
Z- 2 m12
1410aay= 4. 11a
11 - 210y
10 = n-4mv
11= - 2nb + 4m c + tap
12 = b = 4ac
ab ta sxx+ ab + Y ab - a
ab +a Sx -ab + ab a sxx ab- nab ea xx
aa + a  - xX taa + Vaa Da Y-xx taa = y
man
c
Ls
ergo aa ta rxx taa + aa -ais- xx + aa F2 1(() + X F a) = yy
el
seu y = 2aa  +2XX 
Vaa + a d  taa = co fit: Co = aa F a Yaa -x
et co - 2aac0W (+ a) = (a - a a XX. fit
AX = C 12an -cdco
Quid si
2
mmm
ax + ax + 4X + ax - a Vax - XX = y
fil yy = 2ax  fa X∞ + aXC aa xx
C
seu y = 2)
2
-
(axX - 2a Xa +co = - aX Ha a xY, et sit X. To
et fit X = C0: 2aco- a
sit X vo = aX + XX = vvxx fit - a + a X = e0x
aa
seu X = a:, a- v et dx = t. a  dv: (2(a- v
vWXX = av: PJac- vr fit
3
ut x codx = 2a pdv 4 + a VV
seu Cddx=
W dx --
2a vde
(3 aa- x
2a v do
3aa- vn
H) aquv a- V
Ptan-o
y al avor av (+ avr,
atV
a Sa  vdo reduci potest
ad Vae at t aagydus.
sa  a r ud reduciept ad sa rna dus
atv dn=ax du V, vel 8 a +b = a a Z2. et v.
scribe Sa + V = aZ + BV a + V) = aa Z Z + 2g a ZV + aBCV
B ergo v = a Yna- 2
an
eu
a
aco + bC +C
meo +nco +p.