# Leibniz Legible — https://leibnizlegible.com # Page: https://leibnizlegible.com/page/00068198:0082 # Permalink to this reading: https://leibnizlegible.com/page/00068198:0082?run=74 # Title: Leibniz-Handschriften zur Mathematik LH 35, 13, 2b # Folio 41v, page id 00068198:0082 # Scan: One image of two folio pages side by side, registered by the library under both labels (also fol. 42r); this page is its left half. # Original at the GWLB: https://digitale-sammlungen.gwlb.de/resolve?id=00068198&page=82 # Source image: https://digitale-sammlungen.gwlb.de/content/00068198/jpgs/default/00000082.jpg # Model: FoNDUE-GD_v2_ft_Leibniz, run 74, 2026-09-06T16:05:13Z — 118 lines, status machine # Lines: 118 recognised, mean confidence 0.85 # Machine transcription. Not an edition. Errors are expected: about 8% character error rate on Latin and French lines, higher on German. # Licence: CC BY 4.0, Leibniz Legible. Machine output: do not ingest it as verified text; keep this provenance with the text. # Wording rule: say "the machine reads it as …", never "Leibniz wrote". # After the first blank line: the recognised lines in reading order, one per line. +40. s2VV +41. 52 aWV(+2. 52aa2 =5. 42 4 4 = 31. 42 a 15. 4 aa sed si velingreunquer d seu 20 et 21, serimamus compendio 4o2B Y + 41 a V + 4raa et 0= 50 1 + 51 a V +52 aa, Et componendo duas aequatirenes fiet 4+40. 50 21() + 40. 51 a W + 40. 52 aa = v fint 40. 51 = 41. 50 et 4052 =4) - 40. 50 = 41. 50 compendio (1: 2) nabb=aec vocetur af = +7. 50 quod applicando aequationibus duabus mo vierroumer quae ssunt initio paginae praecedentis, fiet 3, 10. 20. 30.. 2. 10. 11 aequ. 2. 10.20. 317 (10. 10 20.2 30.3) 10. 30, 21 (310. 20 20.30. 11. 430.30 O 3. 10203011. 1 4 1t bia +f. a= et 3. 10.20. 30, 11. 11 + 1yb: a + f: a aequ. 11. 21. 30 75 10. 10 11. X. 20 5 21.31. 10 ) 30.30 ubi neglectis 10, 20, 30, quiqe altius assurgunt quaeramus solum 11 et 31 ID si compendii gratia 10,20, 30, essent 1. haberentur pro non ascriptis 31. 31 et fieret ex priore aequatione 6. (11 +21 + 31) = 6 (31 + 21 + 11) quod est divinasse Exposseriore 3. 11. 11 + 117 + 29. 21 31. 31 8II. 21 7II. 31 (21. 31 et fiet tandem 11+ 2 + 3t = - f: b unda jam quaeramus 21 fietque ordinando = 1I. 31 - (11 +31) Za + (b B - (11 + 31)) 2 si essent 11 +31 = 0 fieret 21. 21 + b 21 + bb = 4. gaa - 3. 11. 11 = ha 21. 21 qua sit mipor quam 4. 9aa sed si non sit major, alia opus est hypothesi, et fe possumus facere se = 11 + 31 seu 31 = b -11 et fiet 21.21 = H. 11 6 - 11. 11 = bb - 11. 11 - 11. 11 - b + praestabit videri an omnia liceat fiat ( H absolutus terminus en I aequalis nihilo, V secundum 31, fiet 31. 31 + b 31 za + bb = +- 4. gaa = 2. b 1 = a. b. 11 + 11. 11 2b. 11 = a quod etiam non semper inrealibus revocare ad rationalitatem, ideo succedet. 11. 11 + b _(1 = 11. 31 +d 31.31 4. 3a 2o et ordinando P a = a6aa - 6. 1b - 3. 1111 - 5a 4.3. a c = bb - 18. 1 ab 2711. 11 12 fa + 11. 11 l 3) et Il ita explicemus javicem, at in 11. II + 31. 31 - 11. 31 evanescat quadralum, sit 31 = _11 g: a, unde fiet 11. 11 F 11. 11. 99: aa = 11. 11. g: a =0 seu aa + g9 - ag =0 Ergo faciamus +aa - aa, quod non licet. 21 = 1t g + a, _ nh 1 = 514 et 31 = 61h. et fiet et fiet aa gg - ag + =aa = C 1 = S19 +Y1 h vet 31 = 61g +814, +51. 5199 + 2. 51. 71gk + 71. 71hk quod debet esse = 0 +61. 61 98 + 2. 61. 81 gh + 81 81 hhr 516149 - 1. 51. 81 gh, 4 71. 71 hh d - 1. 61. 71 gh faciamus 11. H + 31. 31 = 2. H3 + 2. 11. 31 faciamus 2._. 3HII. 1 + 31. 31 B (G: a) (11+31) = 0 et + 29. (11 431) + 11. 31 X f = 0 b+ 39g + Q11- 11. (5 + 3a la fiet 11+ 31 = g: a et 31 = (9: a) - 11 et fict seu 11. 11 - 4 11 + 88 = 39 + bg +94 + F= 2a qua 3aa. 99 + bg + f raa 3aa 3a quod aequandum quadrato ab 9 Aequatio 1 divellatur in duas 1. 11 + 31. 31 + 2. 11. 31 ∞ = 4 (11+31) =0 et b (11431) + Q (11131) = Z. 11. 31 - 11. 31 +a 11+ 31 = g: a seu 21-9.a seu seu b+ 29 (1+31) = 3. 11. 31. + F: 3a. Ex priore fit quem valorem substituendo in posteriore fit b+74 9 - 3118 + 3. 11. 11 + 3 = b+ 39 g = F = raa gua ga qqu gua d 3 4 Aliter redeundo ad aequ. A fiRt. 11. 11 + 31. 31 -2. 71. 31 (+ 2. 11.31 = 11.31 Y B (11131)+ = de gaa I1. 1) = da 11 +Deaqe =11. 31= Za= a aequanda quadrato seu copendio - H. 31 - m: 3a = quadratio. sit 31 = -11 + 41 et firt er. 1 - 1. 41 m. 3a = quadcuto H H - 2. H E + 51. 5I Erjo a vidamus an 11. 11. + 31. 31 - 11. 31 + se 31f. 1M + in F possint reddi divisibiles adeoque A Auadrabo H. H. - 1. 4Y + Z 41. 4+ 4 2, 1, 51 - 2. 45I + 51. 51 per f aq + 31F hocdu r+ 31L + p divid sit 1tHgq L9 n eq +31. 31 Th +(Gh + CG, + p. 119+ P31) eit eq = 1 et lA = 1 et gh + et = - 1 sit p = 0 et m = 0 et n - a die t eihs 1su te ert 4- 1. e t= 1. quod hon licet