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# Title: Leibniz-Handschriften zur Mathematik LH 35, 13, 2b
# Folio 47v, page id 00068198:0094
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Unde colligere mihi posse videor hoc notabile
quod cura idem pro si quaestro formetur ex concursu
lineam ordinati positione datam, problema sit
deferminatum. Sed si id problema revocatur ad
du:dx esse indeterminatum, quod notatu dignissimum
ponamus in aequatione Aequationem ad curvam esse exprimi per, y et e
dissemulando X et a   et ex premendo tantum per 10,  etc vel similra
Hujus aequati Haec aequatio sit 1.) Hanc differentiando secundum y et X, dissimulis
fiet aequatio exprimens propuetatem dTangenitium hujus curvae. Quod
si ope harum duariun aequs. Tollatur e e habebitur aequatio 3)
curvam cujus anent cuquam aliquam diterminans per tangentium
propretates
sed eadem curva determinabitur absolute, si
100F 110 C + 171 Cy + 120∞e +  121 eey + 130 e3 + etc. 
aequatioi differemretur secundum e.
sit aequalio 0d)
1029y
112 e97 103y3
differentiando, divo + duo e + dii ey + di2o ee + d12o ecy + 430 P t etc
dior yy du2 eyy 103y
Ldes,  = (1o1 + 11IC +121eCS r)  +131C3+141e et c)
(102+ 112, + 122 + 1322+ 1424 etc) 2ydy
(103 = 113 C + 123C + 133C+ 123 C + ex) 3yy dy
Quod si tollamus e ope aequ. 1 et 2 prodibit aeq. 3, in qua dus et y, quae coincidere
debet cum aequ. dtaaliqua differentiati data 4 cijus solutionem quaerimus;
vel saltem ita ut tollendo utrobique dus, fiat identica. Sed hoc posito oportet
utique etiam ipsam dalam 3 adhibendo, et ejus ope tollendo du fieri aequatio5
+ exaeq. fit dioo + duoe + duey duoee + et
exaq. E fiet  viex uxxe 
0= Yfic
diro ee
12IXX eC
d130(3
131XX C3
diorgus
o1 
ame
ponamus omnes numeros evanescere, ubi est
2 et 3 in fine fiet
100 = d100X 10IXX X 10 = duo + IIIXX 102 = A1o2 + 101
1I = d 1II
extyus
ax
 120 = d12o XC FIIXX
102 = 0
Sed revera video eandem
esse difficultatem, ac si
aequatoI esset secundum Ry
solum et ex ejius differentuade
ltteretur dus per datam, neque
liont quicquam adhunc
spostum assumta e
itaque vereor ut hoc ad
problemate solvenda
prosit