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# Title: Leibniz-Handschriften zur Mathematik LH 35, 13, 2b
# Folio 56v, page id 00068198:0112
# Scan: One image of two folio pages side by side, registered by the library under both labels (also fol. 55r); this page is its left half.
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# Model: FoNDUE-GD_v2_ft_Leibniz, run 74, 2026-09-06T16:05:13Z — 113 lines, status machine
# Lines: 113 recognised, mean confidence 0.80
# Machine transcription. Not an edition. Errors are expected: about 8% character error rate on Latin and French lines, higher on German.
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# After the first blank line: the recognised lines in reading order, one per line.

ponamus jam ex 10, 11, 12, etc. solam esse 10 = Xx et 12 = 1 et reliquis 0
20 - =aa, caetera esse 0, fiet d12 0 20
etq esse o
 Hoc cat  H aititunt  tur a dio  o
Ex terminis ultimissiet 10. ∞. 1. 41
Expenultimis
Exantessenullimis
Ex penantesmultinis
Exanto penantep enullinis
42 1134 siato
cvancesicumtu ige
evanescnt sequentes
egq et sit 412353)
ve A92 5- 3. 33. In
et 43 sevari pt
10 f0.3. g2 + v 1.14
1. 10. 10. 745
+20.20d30
0=10 4 2y7
(1) = 10. 20d40 + 20: 40 1 410. 20. 1.3) X
+2020 d31 +209220  = 1020d4) 420. 4410 1D. V. 231 X
2020 432
10. 30.3.33
Exaequ. A
valubus puanti a G ag . D3X = 5 d42 1, 32ar + 20.dd +-da
sed sic debet esse constans,
o
s
220 4
bique, ata s
Ex  
sa; quant. tes vero
1, 32133,40,41,42. 40
t Melhodo a meaubi
1.N Ya + 20 ( (2de nte do) t L(re datd Ha). L dl 4 1
=+d40
6. 12
dar die q + 1e d2
D1211
Exaeg. 3, habetur d4o cum i in segeatibus
ndisata
Exaeq. 1 habetur 30, cum nuspiam alibi redeat.
non redeat itaque aeqq. (et 3 carere possum 1 et Z sunt expedita. per ae
per aeq. 2. habetur d3i, quoniam 31 in aeq9 4 et 5 quae supersunt non
denique per eg. 5, habetur 33. ita omnia sunt
per aeq. A habetur 32
per aeg. 2. reperta per 5 33 =- 5 d42 it d. 33= 31. 42 20 dd 42 - 3 d 41
ENZ117.
2. 1010 42 = 2. 10. . 40. seu explicato 32
XBP. 22020 9
(d31 = Eod41 rde  +  C2. 1 3
d31 = (10 d41) + di8 41 + 2. 1, 3 19 42 ( 210. 20, 4d 92 (-240 = d4)) = 21or. 1 - 2. t0n 90
70 23.12
d40 = 4. 10. 12. 41 + 200 20 d32 (- 10. 20 d42) - 1 20d0 42 - 12. 20_3) (+ 1020 d44
20 20
per aeq. 3,
dEo subslitendo valoem sit d30 = 1  10 2(4 10. .
20.20c
10 20d 2 - +
20 12
12320
12.20
41. ubi prodes
2020
40 g2 ( 1 3)+ dio 40 (+ 3D ( 10. 10 4)
Ex his videturfieri posse 42 = 0 et erit 33 =0, et 32 = = d41
120 2020
sed video in eo etratum, quod praetervidi 40 latere in aeg. 2. etque ita ex aeq i per aeq. 3 non tolli
Ergo per aeq. 2 et 4 tollatur 32 bis, fiot 3E B.  42, +   19. 40 4 20. d31 - 2 d41 - 41041. Et ex
aeq. 4 fil 32 (= 3. 10 42 + 20193 - = d 41  ) 318 42 = 20 4142 - = d41. quos duos valore H
equado fet de C 1405.1    112. 40 - 404 = 21092 - 20 d g2 - 20 d 34
tine
ficlus 41 = 218. 1240 10
20. adgepit
esceret d4+. tque aded habemus hine H absonte
2 d3] in 2 2. 10 240 42. Et ita habemus valorem
d10 210. 2 1 2 dio, 20.
dio 2.312
ipsias d31 sed cundem 1 per 40. sed ertudem ex aequ 3 pottem habere sine 40 explicando  d32
per posterictem calorur seu per aq. 4. edc Hos duos rs aquando habetur  
Hinc jam habetur 40, atque adeo et gx 40. sed rursus ex aeque 3. habetur a40 sine 40, dum 2 explicatur
per valorem unde abest 40, atque ita habebitur aequalio in qua 31, d31, dd3i et 41, da1 Ad 41, et
42, d42, dd 42, d42 quae cum sit novisima nec, incognitae invicem ducantur, assumman
tur 31 et 41 sic ut se mutuo tollantu restabunt tantum ac, d4, et dd41,  et assumto 42
pro arcirio habebitur 41, atque adeu et d d 41; adeoque caetera omnia. Est ergo
pro artitrio abebi 2.10 42+ 20 de 41 20 20. d42e - 20, 20 d31. Et fiet ad
d40 = 5 d
42 + 210 d42 + g2odio 1 + 30 di0 d 41=
2.10.12
100) d 4r- 2020 43 42 2  1o n.
quae plr aey3  = 4.1041 + 20 d32 (  d43 -  42 (+ 1 A42. 3 Et pro set 433 ponendo valorem ex aeq. 4. fie l
quos duos
d40 = 4. 1 41 -   42 + 3d (1) 42 + 3. 10 d92 - L d (20)dd 42 - f 2 d3 42 - L dd 41 = 31
 ipsius a40 valores s et 4 aequando, fiat d(. 6d0) 41 = 4. 10. 41 - 31  0 seu 3) = (4. 10 (D - 1s2. d )) 4
unde ducendo d31 et dd 31 per  sed ta non possumus evitare quid maneat 4), d4t, dd4r
Nota sit 432b fit ergo d+2 + 3. 3) =0
0 S.M 
.1D. 10, 3. 43
10.12.. 42 M
10404
10.128. 43
a
A (3)= 12. 20 at 20. 42d10 12 20. 1. 31
10.20d42
1220. 141
1020d43
5) = n. 20 dar
1020444
10. 10.9.7)
20. 44d10 1220393 X
19204.175.
20. 43d10
20.20451