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# Title: Leibniz-Handschriften zur Mathematik LH 35, 13, 2b
# Folio 208r, page id 00068198:0415
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a
2
(0021 31 = e_ ovk 00. 11X : 700r - 11C V = - b ( = A - b  = -a
t  - 00. I1 (2M +Y) +, 00 H (2V + M) - 00V =0( 31= aa: (- b a 
palo)(ab(, 1-1
a (2 = 00 - 11131, 1:, 00+1+) Et 32 7 00 +11- 31, 31., 00 + 1142
Si  Non licet facere 11 = 31, nec 0+11+31 =8 et a est majusquam b, et ambo affirmativa
Si Sit 11 = 1 fit n = V quod non licet si 11= +1, omnescunt  eY fit 31 = l, et 11= 31 contra intentum
L2
Si Y = 2 fit V = 2M et - b = 2a - b et b = 2a, quod non licet quia a major. si 11 = - 2 fit a = (3: 2)6 quod
a b
aa: b = I1.,
Si 11 = 3 fiat - 27 n - 18M - 91 - 6Y - 3M - V = 0 2943.  - (, 9 + 3.64 3)  + (9 +6+ 1) V = 0
ubi exanescunt fieret M+VL a seu b - -b, seu b =0 quod non lic et feret d ntY =0 seu BB a b = b seub
si A 3 fit 27 - 8n - gr + 6Y + 3n -V = o seu 1 = qV peu  quod licet. Et fiet
Et fiet 31- 3a:, - 4b f3ae et (rit 31 = 3a:0 quod non licel.
sit 11 = 3 fir 27n -18M - gY + 6V + 3n - V seu 12(n XAY - 4V =0 seu 3M, V -0 seu 3a- 2b
2m+Y = 2a - 26eb = 24 -3b
a
20
2r- = 2b - a +b =
Sit 11 =  fit M t B  n- 4 n - 2Y + qV + 4n - 8V = 0 fit n = EV et a - b = - 2b
quod non licet qura A b foret major quam a
et a = = b quod non licet quia a debet esse affirmativa sit a = - Z firt - ( - 4(-21 - 8r - 4 - 8V
fint q -, qu + 18V = 0 seu p = - 2V seu a - b = 2b seu a = 3b. (ret 3 = 3:, 3b+a, seu
3i = a : 1 -3b +a et sit 31 = = 1:0 Gerralib s
11= Z sit p - bn - 31Y +3  sit s 18M + gV - 27V =0 et fiet
13M = 2IV. et 1a Bb2-21b seu 13a = -8b quod non licet, sit enim a minor
a = =  fiat - ( - 6M - 3V - 18n - 9V - 27Y. fito 25 (n 4 39Y seu 254 -25b = 439b
seu 25a = 146, et 31 = 1 a: pali ca el  C  = 1., 4b +a,
en 3) =  aa:, a  4 25a et  3. 3(-1 ., 1- 50 = 127 l, 2 -7
=00 + H +31 = -1_ 1 7 8+ 1 = 2 Ergo omnia sic procedunt: si rectus
14
est calculus quod repetendum sed ita esset a minor quam b
227)
1g
R sit 11= Z firc da 3. 42p -3. 41 +9. 2. 2V + 9. 2n - 27Y = 0 136F 24)2(
-12)
+18)
seu 2M = 3V =0 seu 2a -2b = 3b fit a = == b  sed abet gess affirmativa
12 - = = -8 n e24M - 12V - 92 (36V - 18M = 27Y se 150n + 49V
s
seu hoa - sob = 49b =99b a =  b =  qu
31 = a: - 5b +Za f 268 a: 250 a + 2a = 99:: 52
II
1B - = + 99 = 11V 1
10
L
99
ut
250
nLWEntHI(2VEA - V
idu
+ 1Ba
 ipb (
+iBa, b 20
3 6. 13 
d.R 5. 13
et lint a: b. =  1(   V4315 B, 3114: 1,:, 11 - 2. 11 + 11
2C = 1 a :g - ba  + 1b HBD = b + 11 (a - )
seu A2 3 = N.G H k V nanC
+
1 = 
-2 +2 =4
11
a
31
H- 31 = L
12 = 113 1 - 11131 = 272 = Z  2 32 = 32
Habemus ergo 11 = 2
nea
= 11 = 1, :
a seu it = b  - 11b +11
a
9
qu (11 - 1) 1
a
2 2 -4 +2 = 2, h -2 +1 ∞2, L- 1-8
Errgo a : b = 3: 2 1=2, 3 = 3:2
- 00 + 31 + 11 = 5: 2
= 1 + 11+3C
5:2
31
52
tatu -b
1. 2a + p2b( 1bZ 3. 11b - 2. 11b rua = f ub L b = 0) bd 1563 36
seu si a : b = a cab (1 - 1) D : 11 quadr (11 - 1) seu a = 11 - 1 + 2
et
51=
tec
31
B
12 = 2:5
11+31 =  7:2
1 +11. 31
00 + ur3I
31 = 3:2
912
5. 2
= B 9 -32
t 10
32 = 9: 10 a: b = 2: 2
a-