# Leibniz Legible — https://leibnizlegible.com # Page: https://leibnizlegible.com/page/00068200:0059 # Permalink to this reading: https://leibnizlegible.com/page/00068200:0059?run=74 # Title: Leibniz-Handschriften zur Mathematik LH 35, 13, 3 (shelfmark LH 13, 3) # Folio 30r, page id 00068200:0059 # Scan: One image of two folio pages side by side, registered by the library under both labels (also fol. 29v); this page is its right half. # Original at the GWLB: https://digitale-sammlungen.gwlb.de/resolve?id=00068200&page=59 # Source image: https://digitale-sammlungen.gwlb.de/content/00068200/jpgs/default/00000059.jpg # Model: FoNDUE-GD_v2_ft_Leibniz, run 74, 2026-09-06T16:05:13Z — 52 lines, status machine # Lines: 52 recognised, mean confidence 0.81 # Machine transcription. Not an edition. Errors are expected: about 8% character error rate on Latin and French lines, higher on German. # Licence: CC BY 4.0, Leibniz Legible. Machine output: do not ingest it as verified text; keep this provenance with the text. # Wording rule: say "the machine reads it as …", never "Leibniz wrote". # After the first blank line: the recognised lines in reading order, one per line. co (0) X.F scil A - n = X - X+ = pX. X. 1 u vtr h quaentur X quaeritur qualis sit relatio ista e X. X 1+Z X. X 1 sit B, et X sit O D . X 1 D: () = n X (∞) (7 F. X O- A (∞) = D et et X. X=, log n= log. D. seu log3 - log (D) =) 2X log. n et fiet X= log D- log D): Elog. n Ergo Elog. D. = log 1) logD - log() - 1 = log. V quae est relatio generalis inter, D et (D, C - (0) = D et (0) -(()) = (9) X. X =1 pr. X1 seu 3 - (1) = _ n (4) nea 1- 2t 2. logn l aD - d2 = , XX E 1: n - n - 1 + n =+1 X Si renuntient A sactur 1, 3,7 13 Ed an hoec edant suo XFI. X similiter g(. X.1 + X XF RX+1 erqu 21 B jactui 25=10 17 nenter aliquid perdidit Ergo a - n + n + n + n est ad b = e n + n + n erc: ut a ad b a + b. 1= n = 1) a = n - n 4 n - n + n -n 6 et b 1 - n b = n - n + n - n + n - n et et fit a2 ( sit n + n + n erc = O et n + n + n = D. fiet a = 0 : b - D:: a: b seu (ab) = 0b = (a b) = a Ergo fit a: b :: O: D rursus In i= n a = O - D et 1 n a+b =1 His inter se junctis aequationibus fieret D = O - na = Ob: a ergo fieret. O = i=naa: a - b. sed b = 1: 1 n - a E Ergo habetur relatio inter C et a, sed nondim nova inter a et b Et quidem dubilo de tota ista rationuade = XX - X + XXAX - 7 1IX XHX ec = n n = p 1: H - n XX - X XX + X ex