# Leibniz Legible — https://leibnizlegible.com
# Page: https://leibnizlegible.com/page/00068200:0133
# Permalink to this reading: https://leibnizlegible.com/page/00068200:0133?run=74
# Title: Leibniz-Handschriften zur Mathematik LH 35, 13, 3 (shelfmark LH 13, 3)
# Folio 66r, page id 00068200:0133
# Original at the GWLB: https://digitale-sammlungen.gwlb.de/resolve?id=00068200&page=133
# Source image: https://digitale-sammlungen.gwlb.de/content/00068200/jpgs/default/00000133.jpg
# Model: FoNDUE-GD_v2_ft_Leibniz, run 74, 2026-09-06T16:05:13Z — 76 lines, status machine
# Lines: 76 recognised, mean confidence 0.77
# Machine transcription. Not an edition. Errors are expected: about 8% character error rate on Latin and French lines, higher on German.
# Licence: CC BY 4.0, Leibniz Legible. Machine output: do not ingest it as verified text; keep this provenance with the text.
# Wording rule: say "the machine reads it as …", never "Leibniz wrote".
# After the first blank line: the recognised lines in reading order, one per line.

fas ita investigabimus:
P  ego co. deaego b sdx + fAF dx. Ergo Sd+ Fxk ex  aeu
X aequ co X (+ co 4x e dx
e
dx
Et du cd aequ
X
XX
p
ac
 exis 
Cx - X de aequ dco. Ergo sd aequ s aax - (de
idem alio calculo
eem
XX n
X
Jam es de datur est enim aequ.  dx+ fxx ax. quod
datur Habe ex quadratura Conica, habemus ergo
e dx
p
gadratura figurae
Eadem methodo habebimus et. e aequ
X
sit:
ec C esx bo exte
b +
nam
.Nam pro b+ cx substituamus
IV. Idque inseramus in e vel de loco X. manebit Canica calculus,
1
t
Sa
pdor succedet, eodem modo. Tandem ergo pulcherrimum
problema absolvimus imposuimusque inquisitioni tamdiu
agitatae finem
sit . (b+ cxx aequ n.
ftes quaritur quadratura: Ax
q aeqe na d ve +hva aequ. lv+ Macm e48. +9
3
g do e + gDCc + Ma v + h Vda rgo do +m La +2 de + d
duaeqo ap 9 de V (, ge + ha =
Ergo du aequ.
-h
aequ:e +
ge +hafl
ge +ha-
yae +h da +dl
(2) getha- 1
si detur ydx. Et 1 dx et
Ety ex+ x + L dus +(
V aequ V
b2 + CXX)
2
 HEvdo aequ
45+gri
x dus
et
per ebalutione
Gu: WL. GL
Lec
PN. NM. pM
seu itus ago d
dx
dque
Ergo tq aequ. ex
cy
 dy estantem Eyrego x b
2
Ergo dus aego ydx
Ergo summmra yt du + ux senoaegos b 
2CX dx f2+gXX = s
Lis
F+gXX
cuiu
quadrati
29Xdx b+CXN quaerit