# Leibniz Legible — https://leibnizlegible.com # Page: https://leibnizlegible.com/page/00068201:0107 # Permalink to this reading: https://leibnizlegible.com/page/00068201:0107?run=74 # Title: Leibniz-Handschriften zur Mathematik LH 35, 14, 1 # Folio 54r, page id 00068201:0107 # Scan: One image of two folio pages side by side, registered by the library under both labels (also fol. 55v); this page is its right half. # Original at the GWLB: https://digitale-sammlungen.gwlb.de/resolve?id=00068201&page=107 # Source image: https://digitale-sammlungen.gwlb.de/content/00068201/jpgs/default/00000107.jpg # Model: FoNDUE-GD_v2_ft_Leibniz, run 74, 2026-09-06T16:05:13Z — 119 lines, status machine # Lines: 119 recognised, mean confidence 0.76 # Machine transcription. Not an edition. Errors are expected: about 8% character error rate on Latin and French lines, higher on German. # Licence: CC BY 4.0, Leibniz Legible. Machine output: do not ingest it as verified text; keep this provenance with the text. # Wording rule: say "the machine reads it as …", never "Leibniz wrote". # After the first blank line: the recognised lines in reading order, one per line. cD DF V ax CDwVaraz +b222 FFV ab , ax ca 2ia 262- 2a262+6a24246222 Conferatur son traluu XY - d by 62 ndeo X Sa tbIE unde β X 3+ allax- aex + ry Yn arer 1b222 a2b4222a26323 + c262 ∞4 aab2X2 = 2a 4b X 3 + a2c2 24 2b4 cognitur y +X ( a problema: Data basi Trianguli, pectangulo sub duobus lateribus, et angulo a uno ad basin, reliqua invenire. Esto DE basis = a. VEG In Triangulo CDE esto data basis DE = a. angulus CDE, et rectangulur CDX C CE. Dabitur ergo ed recta GE,. = b. eritque Esto CF -X erit X = DF ideoque DF = ax : et DF a et scit 6D = a X + bX sie X aerbe et CD = X aut EF L a = aX, ejus et EF = a = 2ax + a X = a b- 2abx + ax et CE = a.b - 2a bX + ae X + b X et BE, C X - rab X s Ergo e CD CE = t arrat 61 Ergo X e l D Ergo conditio de rectangulo inepte adjicitro ontra si ditio de rectangulo nepte adjicitu rectangulum. Omisso ergo angulo, quaeramus a seu CDB a ae 1 E Ergo CE eot axti ca 1 + 2b 14 X est aequatio ad Paribolam seu cLY et cum proposita ad ciiculum ceo habolae + b+ 4 X diet agu gulum posito ram a = 1. fiet. Erit ergo CDCGEB a X Ergo a X y quae cvcu o ab AEb 2ab 1b2X + bX L C. 4 -2 + b3X 23 + H =2 62 +b2 X : C-1 = 0. sollatur secundus terminus, poneuto Zu f 2b +b3 Sublato secundo termino, patet problema esse planum trage spt n CF DsC DZV a C auterut by X, C b3 a X la cont m friore ad circulum dat aequatioum arbr-2a2ba tar unius incognitae, renge X a a X quae est plana fit ergo problema planum sBIBLIOTHBEA RBCEA X HANHOVENAie arib2 vr CF=X. XA = Y CD= fa X +b X = 7 sa 2b FE=a bX et F5 = a 6 bx eX fiet Y+ X = a b-x + A seu V +k. X + 24X - a = 0 locus est ciurculus XC sa , 6. 2y = da Ieu x = dab locus est Hyperbola ratio b2 v B+ E a C= cognita productum ex DCCE a CX b DEVC ab dea a cEcd 1 at - 2a x+c b2 - 2a2b∞ + c2X2 et ab 8 fiet C5 dL 2243Y Cab LaX a 2a 4bx3 -2 a2c2 X4 ∞ dab4. b 2ex+X d seue = vel Ce seb. 2 ex +X o eb - 2 ex + X d miletu C . 0v. e + X ves +∞ 2 e Aitc