# Leibniz Legible — https://leibnizlegible.com # Page: https://leibnizlegible.com/page/00068207:0059 # Permalink to this reading: https://leibnizlegible.com/page/00068207:0059?run=74 # Title: Leibniz-Handschriften zur Mathematik LH 35, 15, 5 # Folio 31r, page id 00068207:0059 # Original at the GWLB: https://digitale-sammlungen.gwlb.de/resolve?id=00068207&page=59 # Source image: https://digitale-sammlungen.gwlb.de/content/00068207/jpgs/default/00000059.jpg # Model: FoNDUE-GD_v2_ft_Leibniz, run 74, 2026-09-06T16:05:13Z — 25 lines, status machine # Lines: 25 recognised, mean confidence 0.90 # Machine transcription. Not an edition. Errors are expected: about 8% character error rate on Latin and French lines, higher on German. # Licence: CC BY 4.0, Leibniz Legible. Machine output: do not ingest it as verified text; keep this provenance with the text. # Wording rule: say "the machine reads it as …", never "Leibniz wrote". # After the first blank line: the recognised lines in reading order, one per line. Eurerit mensuratio portionis Lunule ADEA. Quod ut fiat quaercndum ett ejus elementum, ac summandum Id Elomentum e ED (∞) (C), id ett Triang. CD (D) = triang. CE (E). Est autem CD(∞) =D (D) in =CT. AG tit X; GD, y; 1F, 2; FE, v. AB seu BC seu BD, a. CE, fraa. D(∞) = dxa: y. sit BL parallela et aequal. DF; pat et triangula BL C et BGD congrua etse seu aequalia et similia, nam ang. BeL aq. angulo BDG; comprehendunt enim parallelis; itaque triangula BLC et BGD sunt similia, sed hypotenutae BC et AD sunt aequales; Ergo et tirangula simi- lin et aequalia. Itaji C = DG. Itaq CT = a + y. (=DH). Ergo CD (8) = a Fy, adx: 27; sed X = a - Van gy. Ergo da = ydy: Taayy, et CD() = ady 1a +y,: ay: 2. quaeramus jam et Ce(C) = E (C) in =CC. Et autem E(C) = dz fraa: v. Ergo CE(C) = dz aa: v. quaeramus ergo Z et v per y. Nempo ob triangula similia HC et EFC fiit EF un v: OH un ady:: CE uu fraa: CD. Ert autem CD= OH LCH, seu = a + ray +yy +aa-yy. Ergo CD = Fran +2ag. Ergo fit v= laatag. Jam Wv + CF= 2aa (seu FE +CF= CE) seu an tay +CF= raa. Ergo CF = Jan -ag. Ergo Q (Bia - CF) = Fraa Jaa-ay, et hinc aZ = ady: 2 Paa = ay. Ergo CE (E) seu duan: γ = audy: 2 aa yy. Ergo CD (D) = CE(E) = aa tay dy = andy,: 2V ar- yy = aydy: 27 aa yy = =ED (D) (E). Sed sum. ED(D) (C) = ADCA, et s, aydy: 2laa yy = ra, a Vaa- yy = 2 ax = Triang. CAG; Ergo CAG = AD EA, ut erat propositum. Si omnia fuissent explicata por Xe Ploco y) faclior fuiset sumatio; nam aydy: raa yus dat ada, adeoque ED (D) (E) aeq. triang. CG (G). Haqe propositum thcoroma succedit, nempo quod triangulum CAG aequatum lanulae portioni Adcit, quod et peuimen Methoti nottra g.