# Leibniz Legible — https://leibnizlegible.com # Page: https://leibnizlegible.com/page/00068255:0061 # Permalink to this reading: https://leibnizlegible.com/page/00068255:0061?run=74 # Title: Leibniz-Handschriften zur Mathematik LH 35, 3 B 5 # Folio 31r, page id 00068255:0061 # Scan: One image of two folio pages side by side, registered by the library under both labels (also fol. 32v); this page is its right half. # Original at the GWLB: https://digitale-sammlungen.gwlb.de/resolve?id=00068255&page=61 # Source image: https://digitale-sammlungen.gwlb.de/content/00068255/jpgs/default/00000061.jpg # Model: FoNDUE-GD_v2_ft_Leibniz, run 74, 2026-09-06T16:05:13Z — 98 lines, status machine # Lines: 98 recognised, mean confidence 0.84 # Machine transcription. Not an edition. Errors are expected: about 8% character error rate on Latin and French lines, higher on German. # Licence: CC BY 4.0, Leibniz Legible. Machine output: do not ingest it as verified text; keep this provenance with the text. # Wording rule: say "the machine reads it as …", never "Leibniz wrote". # After the first blank line: the recognised lines in reading order, one per line. A sa Et +1 1+a F al -al = al =at e ndi paritu e la jc P il Ita al -al +al + a -al + a -2al a plici ut ante El a Divisio dyarithmica ice Notatu diguum 1ceseetb et Si a = 0 et l = 0 fit X = 1 si sie a = 1 et l = O fit X = 1 sit sin a = 1 et L = 1 fib X - 1 Si a = 0 et l = 1 fit X =0 sit X= 410, 2a + 1l + 13 al si a et b 20 fit = 10 = C si a a = , e C e = 0 fit X = 1 + 11 = 1. Erp si a = c et l = 1 fit X = 1 + 12 = 0. Ergo 12 = - Denique si a = 1 et l = 1 fit X = 1 - 1 + 13 = 1. Ergo 13= 1 Et tandem genicaliter X = 1 -. L + al sit y = 10 + na + 13b + 13 l + 14 alri5 B l+ 16 ab + 17 ac Si a = 0 et b = 0 et l=0 fit y = 0 ergo 10 =0 si l= 0 et a = 1 et b = 0 fit y = 1 = 11. sin a = Det b = 1 fCy 20 Nin a = 1 et b - i fit y = 1 = v + 16 fit1 b e Si l = 1 et a = 0 e b =0 fit y = 1 = 13 sin a = l et b -0 fit g fit y = 0 = 12 fit 9 -0 = 1 + 1 + 14 et 14 = = 2. sin a = 0 et b- fit y = 1 = 1 + 15 et 15 =0 sin a= 1 et b = fit y-0 = , + 1 = 2 + 17. Ergo 17 =0 et tundem erit generaliter y = a + l - 2al e si a = 1 fit X - 1 si a = 0 et b = 0 sit X20 el -al si a = O et b = 1 et C = 1 fit X =1 fit X = atb -ab- b + ab + abl + bc ( abe si A = 0 et b = 1 et c = 0 et la0 fi1 X - 1 si a =0 et b = 1 et C = 0 et l = 1 filXe 2 X = 10 + 1a + 2b+ BC+ 14 L+ 15 ab+ I6aC + 1 7bC + 18 al+ iu bl + 20 clt 2t abeF + 7 abc + 2 ab l + 23 acl+ 24 bcl + 25 abcl 120 si omnia 0, nempe a, b, C, l, fit X =0. Ergo 10 =0 si a = 0 et b = 0 fit x = 0. si C = 0 et l = 1 fit X = 0 = 14 sin C= 1 et 1=0 fit X ~0 = 13. si C = O et C =) et l = 1 fit X = 0= 20 si a = 0 et b = 1 et c = 0 et = 0 fil X = 1 = 12, siy c = 1 et lc0 fil X = 1 = 11 + 17 Ergo 17 =0 sin C= D et l = 1 fit X = = 14 19 et 19 = - 1 sin C = 1 et l = 1 fit X = 1 = 1 H - 1 + 24 fit 24=1 sit si a = 1 et b = d et c = 0 et l = 0 fit X = 1 - 1 si C sin l = 1 fit X = 1 = 1 + 18. Ergo 18 = 0. sin c = 1 rt (=0 fit x = 1 = 1 + 16 fit 16 =0 sin C- 1 et 1 = 1, fiet X - 1 1 +6+ a 23, seu 16+ + 23 -0 seu 23 - - 16 = 1 + 23 Ergo 23=0 si a = 1 et b = 1 et C = 0 et l-0 fit x1 X = 1 = 1 + 1 + 15 et 15 = -1 sin C = 0 et 1 = 1 fit X = 1 1+ 1 = 1 = 1 + 22 fit 22 = 1. sin C= 1 et l = 0 fit X~I fit X = 1 = 1 + 1 = 1 + 21 Et 21 = 0. sin C = 1 et l=1 fit X = 1 (fit X = 1 - l + al ut aute 11114 1 - 2 Et tandem X = a + b - ab - bl + abe tabl + bel- 2afel. Hine si pro a ponamus opro b, F, , ) = 1 + 1 - 1 = 1 + 1 + 1 + 1 + 25 et 25 = -2 si = sit = A + B - AB - BL + ABC + ABB + BCL - 2ABCL sit aL A = l- al B = a - al = + l = al + a = A + abl +Dabl +al, e +al ab C =b. et et L=l +d - 2al b ut ante pivi damus ... a)b). si a = 1 et h - 1 fit X = 1 si d = 1 et h = 0 et b 0 fit x = 0 si a = 0 et h = D fit A- = +l te sit X = 10 + ua rih. per. hl sed a = 0 et h = 0 incommodum est quod possunt satis facere tam c quam et fit X - 1 =9 et X =0 =0 Ergo XX = 1 X + 1. 0 = 0 seu X - x =0 seu X = sese o,t sit si a= 1 et h = 0 fit X = 0,l + 11 = 0 seu Ergo 11 = = 0,l sit si a = 0 et h = 1 fit X = 0 A = 01 + 12 et 12 = -0, 1 denique si a = l et h = 1 fit X = 1= 0,t F - 0, bt = 0, 1 quod est impossibile, itaque non licet relinquere in divisore generali ellaquere primam incertam licebit dividere per ipsi ergo non licet dividere per h, multo mmus sid si Generaliori adhuc calculo opus non per 1) l sore dividendo per h sed video rem non procedere