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# Title: Leibniz-Handschriften zur Mathematik LH 35, 3 B 5
# Folio 35v, page id 00068255:0070
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x = ath - 2ah ut ante
si G = 0 et d =0 h  fit y = b Z = 1
si a = 1 A 
se epert a 20
b =1 fit
y = b Z=1
si h = 1 et a = 0 et b = 1 fit y = 0
=
si h = _+ et a = 0 et b =0 fit y = 1 et 2=0
y = 1+ ma+ nb + ph a qubstan son + Caba nadi si h= 0 et a =8 fit l +  nb = y sed y - b. Ergo l = 9, H1 n = 1
Si a = 1 at h = 0 et b = d fil y =  ma  sed tunc y = b Eup  = 0 ergo m =0
si a = c et h = 0 et b = 1 fit y=1 sed ex formula y = L + er B, + q ergo g= 0
si a = 1 et h = 1 et b =0 fit g=0 sed exforimnta y = ph + rati ergo p + r = 0 seu r = - p
si a = 1 et h= 1 et
1 fit g = 1 et y = 5+ t = 1 seu  5+ t = 0
si a = 0 et b = 1 et h = 0 fit y = b = 1 = (exformula) 1+ s
5A a =0 et b = 1 et h = 1 fit y = 1 + p + s sed y = 0 ergo p+5 = = 1
sy 4 = 0 et b = 0 et h = 1 fit y , et exformula y = PR = 14, Ergo 5 = = 2 Ergo t= 2
ita tandem y = b + h = ah - 2bh +2
abh
SebR _. sit Z = l4 na + nh + ph + gab + rah + sbh + + abh
si b = 1 fit Z=1 Ergo si a = 0 et R - 0 fit 1 = l + nb. Ergo n = 0 et l = 1 si a = 0 et ha
fit 1 = 1 + p + 5 seu s = - p si a = 1 et h= 0 fit 1 = 1 + m + 9 et g = - m Ma 21 alt - 1
fit 1= 1 (+ n F p FG2(: m + r -D + t seu t = - r
seu 
sin b = D, et a = 0 et h = 0 fit Z = 1 = l, quod jam tum constat si b = 0 et h = 0
et a -1 pt Z = 1 = 1 + m Ergo M = 0. Ergo et g = 0 si b -0 et h = 1 et a = 0 fit
Z = 0 = 1 + p. Ergo p = = 1 et 5=1 si b =0 et h = 1 et d = 1 fiet tan-
dem Z =1 = 1 - 1 + Y. Ergo r = 1 et t= - 1. itaque tandem fit gene-
raliter
+ b
7= 1 - h + ah + bh - abh.
(+ b + a
itaque tandem
ubi patet se per Identicitatem rarsus subesse nan
+ 4
Dh
F4ak)
74bG
- 44b4
+ 2b
(42A)
rat
4bh
+ dabh
+ a
4h
rah)
= 4 + 2b + a - h
seu 11 b 1a
h
sed quia haec inquirendi meds methodus indirectior est, et prolixior, nec nisi
4 Z
in subsidium adhibenda, placet uti directiore tali Nempe quia
jam habemus columnam primam
(+ b a
Nempe cum ab 1)+ b) + a ortit detrahere B
oportet detrahere h,  habenus ex regula subtractionis
simplicae in columna prima a + h = 2ah, et in co
lumnam secundum transferre oportet +ah - h,
addamus ergo prius ati, ad b, fiet +b + ah - 2abh
in columna 2da, et abh transferetur in tertiam.
Nunc praeterea ex columna secunta, id est ex brah
b + ah = 2abh subtrahere oportet h,  Ergo per
regulam subtractionis jam inventam, in ea scribe-
tur + b + ah - 2abh + h, et 2h (b + ah - 2 ab1)
ergo columna ida his in unum collectis erit
b + h = ah = 2bh + 2abh et in columnam
tertiam transferetur h (b + ah - 2 abh) = h.
quod cum t iam in ea extantibus nempe
+1 et abh, dabit columnam tertiam, ceu
1- h + ah + bh - abh. Neque enim hac e hic
regulam additionis oportet applicare, alioqui iretur in columnam quartam
quod fieri non potest. Et judicio est, hanc collectionem non posse excedere
unitatem, quemcumque valorem habeant a, b, h.
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hsctalti)) Intah alabi
2se rabh- dabe)
inebhorah. 2ab2)
itab ex
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ah
rabh
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