# Leibniz Legible — https://leibnizlegible.com # Page: https://leibnizlegible.com/page/00068256:0003 # Permalink to this reading: https://leibnizlegible.com/page/00068256:0003?run=74 # Title: Leibniz-Handschriften zur Mathematik LH 35, 3 B 6 # Folio 2r, page id 00068256:0003 # Original at the GWLB: https://digitale-sammlungen.gwlb.de/resolve?id=00068256&page=3 # Source image: https://digitale-sammlungen.gwlb.de/content/00068256/jpgs/default/00000003.jpg # Model: FoNDUE-GD_v2_ft_Leibniz, run 74, 2026-09-06T16:05:13Z — 172 lines, status machine # Lines: 172 recognised, mean confidence 0.77 # Machine transcription. Not an edition. Errors are expected: about 8% character error rate on Latin and French lines, higher on German. # Licence: CC BY 4.0, Leibniz Legible. Machine output: do not ingest it as verified text; keep this provenance with the text. # Wording rule: say "the machine reads it as …", never "Leibniz wrote". # After the first blank line: the recognised lines in reading order, one per line. 20 Decemb. 1699 pag. 1. pro Fractionibus dyadice exprimendis 105 (001 seu 100 = e1 + 7, et 1 = 0 ot o101 ete 14++ u Nam Ndm = 4B (0∞ 00f s + vel 2010101 eF + 1 orsiaoI l000000 aetrectea 100000000 vel 6 01 010101+ ei eb ex his patet periodum quidem semper descnere in 1. Qualis hoc loco est 01 AXA X, atet Tibobobo 166 (00101B7 vel 0. 010101 vel 0. 0101010101 etc Cat nu seu 101 + seu 10101 + L 100000d 101010101 et 1 0000000000 en patet ex his periodum, ut, hic o OI, semper desinere in 1. et resitrii numeralorem 10000 ()b) esto antib, ita ut si b sit 1 tunc (b sit 0; et si b sit 0, func (6) sit 1 si divisionemfinias semper esse 1 b Theoremat. b + 1= b (6) . Nam A 10 6b1 1(1) = 4 b + (b) = 1 Nam B si b = 1 erit (6) =0 et fit 1+ 0 = 1 b -bb = B3 etc sed b = 1 peo 4 si si diffi seu (6) = 1 - b b (6) =0 P 4. 9(es -0s1 sin b =0 ert (6) =1 et fit 0+ 1 = et b = = b) patet ex praecedenti Nam si b = 1 erit b(b) = lin 0 -0 si b= 0 eut b(b) = 0 in l20 enempe 0 si b =c et 1si b = (C1 B.) BC20 = b uc Ci b2c erit b(e) = 0 et (b)C 20 (C) et (6) C= () (B) = (6) = c et Hic quaelibet t quantitas si bec ent b∞) Cs t vel 0 si a - 6) (1b)C) si molet cec, ert (a) =b si b = C = 1 erit b-c70 si N b posito = p sit C = (K) et b posito (p) sit C = K fint BC) +d) = b(C) + (b) C = 0 vel 1 nunquam + peA _ + = (b) C + P b (p) + C(K) = 1, et (p) = b - bc(K) semper b + c = c+ b = b(C) + (b)c bc erit (1) = (bc) = cb) (C) sit t() B)C dtrosquod sucito ipistma si b =c fit (b c) = (6) CC sin (b) =C fit (b d = bc Nam _ sit, b =c, fit bc = b et (bc) = (b) et (b) (C) = (b) (6) = (b1 Hbc-o X- 2Fh +nh = X + h = 2Xh+ h =Xh4h = 0 X = 0 +h X -X + 2h - 2XF sin (b) =c fit bc = bb) - 0 et (bc) = 1 at 1b) (C) = c() - 0 pordiseum () er de de by ba ce ep u du dn dta E s S B ete il bn n m 1 an am al bm V V d vid 8. pag. nas si b- a sintque ambo positiva erit b20. Nam s si b (c) erit bet c +1) = 6+ ) + si b= (1) erit b() P X, X- 1 =0 a, 4- 1 = 0 = aa - a 22. AXX -2xh-h xu 0, 0-1 =0 1, 1-0 =0 h. ex X- 3Xh+3Xh - h) -x + 2hX = h 20 2lx ata seu X = 0+ b1 smu XX-2Xath X-h.l X3 2K CXth XL+ 2hh h EX +2xh - h 3xh tgh Eh xect. +t2b =1+3h nite a bsc =0 sequenti coliadoud . postsequenti 0 al + 1 = 6 150 Ergo n al =1 adeoque a = l = 1 am +bl + i = i + b + 1 = B 150 fit m+ b = 1 seu m = b) p + b(C) + c(b) + d ∞ 1 = iso mlpo si b = c sit b (C) +b) =0 et p + d + 1 = 1so et prd- 1 et p -Cd) n +b m + c + 1 = n + c + 1 fit e at = 10 fit, n = (c) Sin (b) =C fit b (C) + (1b)= b + (6) = 1 et p + 1+ d + 1 = 1s0 vel ipso , erit p = (d) sin = (b) = P erit p = d unde b b(C) + p(d) = 1 ret p = , - b (C), : (d) = ad3 b(4)d) - () (() )) (d) (b(1)) = p 10 et p - d,. itaque si b =c 1. + b() Cb(0)) 4 Ln) 1 d(b) + e ubi si p = (d) item s seu si P +d = 1 item si p+ d = 0 fit additur 1 in Ergo p+ d = d l sequentem columnam. sin p+ d = 10, addetur 10 in sequentem columnam. Aa poterimus hinc aliquid generale ducere in sequentem columnam addendum 2 id st X. si p+ d = 0 addetur et d + + fiet X = p + d + 1 si p+d_ = 1 fiet X = p+ d sin p+ d = i0 fiet A = p+d Ergo ducantur in se invicem haec tua quibus ductis rationatiter, nam X et xx hiac non sequantur xah L0 vel X-h=0 d per compendium sit p+d = h esto vel X - h - 1 =0 vel +XXh- H. sed ita qu x potest esse 10 seu 2, toem est de h ideo sic sed quia 10 aedi ad columnam sequentem est potius 1 addi columnam post sequentem; = p+ d = 1 it inficem fit aqualio pro X, nempe X= 22x + Exh- procedendum ut columnae sequenti addatur 1 si p+d = o et erit X = p Ad + 1 ad fiet X= p + d sed si p+d = 10 erit X = 0 Ergo X = ++d p p- d et Nam tunc p = d = 1 et ita ducenda in vicem X - 1, X - b - d, X +d - p et fiat XX - 2p X - Dd - pp), X- 1. = X3 - 2 pXX - X (dd PP) + dd-pp et quia P, d, X, sunt ovil 1 fit +X -d ita si pa vel aequatrs. p Cx + 2pX. +d- p vit Y pod vel polius x= +p +d. nam quae aequalio salis facit, nam si d p seu si dep dividatur s 2P∞ - X(d- p( (+2pX sigi si de et pe0 utcunque, sed parum apta calculis -d s Ansic: si es 3 1,d X -d + p, fit denu X = pd - P bra eus erro iam hpli bitu erte crys cugo jam applisibitum cotibe ionum ex sedib t anta generaliter p+ d et (0) conden Quite linea ben ticalis, mini separat X- k - 1 X = h- 1