# Leibniz Legible — https://leibnizlegible.com # Page: https://leibnizlegible.com/page/00068256:0006 # Permalink to this reading: https://leibnizlegible.com/page/00068256:0006?run=74 # Title: Leibniz-Handschriften zur Mathematik LH 35, 3 B 6 # Folio 3v, page id 00068256:0006 # Scan: One image of two folio pages side by side, registered by the library under both labels (also fol. 1r); this page is its left half. # Original at the GWLB: https://digitale-sammlungen.gwlb.de/resolve?id=00068256&page=6 # Source image: https://digitale-sammlungen.gwlb.de/content/00068256/jpgs/default/00000006.jpg # Model: FoNDUE-GD_v2_ft_Leibniz, run 74, 2026-09-06T16:05:13Z — 128 lines, status machine # Lines: 128 recognised, mean confidence 0.80 # Machine transcription. Not an edition. Errors are expected: about 8% character error rate on Latin and French lines, higher on German. # Licence: CC BY 4.0, Leibniz Legible. Machine output: do not ingest it as verified text; keep this provenance with the text. # Wording rule: say "the machine reads it as …", never "Leibniz wrote". # After the first blank line: the recognised lines in reading order, one per line. pag. 4.) sen (()= b (c) + (b)C Quid multa. jam habemus l = b () (b (C) + (b)C). Nam Nam pag. 1. in jam inveneramus si b = c esse b (c) + (b)C = 0 Namtit = b b) + (6) b = 0 + 0 =0 Sin b -() ( c = 1b) fit b (C) + (b) C = bb + cb) (b) = b + (b) = 1. itaque jam tandem omni ambignitate remota fiet X = (b (5) Hb) C) + b(9) + (b) c (d). videamus jam A an Posita b = c sit X = 1, et posita b = c = b) sit X = (d). Nempe si b =c fit X = (b 1b) + 1b) b) + b1) +b) B. (d) = (0) + 01d) = 1 + 0 = 1 Si b) =c fit X = (b b + (b), 6)) +, bb + (6)16) (d) = (b +(b)) + b + b) (3) = (1) +, 1(d) =0 + (d)= d seu b = (c) Aeque ita habetur quaesitum si sit ( + L n + (2) (d) et y = (x) fiet y = (n + ( (d)) = 1 - n - (12) Cd = (1) - 1)(d) = () (e ) 1- D) = d(4 jam ergo Et y = ((b (8) + 1b) c) + b C) + Cb) C 1d)) italu + (n)(d) = (d. itaque y = (b(C) + (b)C) d X = n + (n) d) () = 1 - n et (d 1- d fiet YL L _ n + 1+ nd _d Bn = (∞ CC +1 + nd + (d) -) + sid 2= b() AbsC i sit X = (B) + N(d) et y = (X) fit y = 1 - (d4 d) = ( + cd) = 1 1 nd si X = () + R1d) fit 1E A + - dd et X = (pd) et y = pd itaque tandem X = b() + (6) C5 D) et (b (C) + (HC, d) et y~ b(c) + (6) c Restat ut B melius quam intio, et sine omni ambignitate seu dispunctiortate p+ b(c) PC p+ Z + d + 1 LyX)0 = 500- ∞ 10y + 10X A habentur y et X. Ergo p - + 2d 100 Zd + 10 (2d) et e d - 1. Et quidem reperio. hine si ba c = b fiert p (d), sin _ (C) b p. cum sit Z = fiet p = (d) exprimamus, si licet. sin c = (b) _ fit Z = 1 et p = 100d + 19d) - 10 - d 100) - 10 = - 10, 1 d) = - 10 d et firt p = 100d - 10d - d = d, 100 - 11 = d. verum est ergo quod diximus initio si b - b ext fore p = (d) sin C = (b) fore p = d. videamus an hinc sequatur esse H(C) + P1d) = 1 sune si cab sit sit per compend b(C) + p(d) = W. fiet nam fieret (d) = 1. cum tamen sen (d) d =0 cum possit esse quaecunque. non brevior ipsius p valor haberi possit si 6 = b fit p = 1d) Nesero an sin c = (b) fit p = d Novum et mirabile Analyseos genus est ex ejusmodi conditionalibus ducere, absolutas possum semper, sed non sine ambignitte visicum descenditur ad vruteo rationales b(C) + p(d) =1 sit c- b fit b b) Hdd) = o+ = cet sed hoc non est 1 sed e vel L At paulo difficitius est omnem evilare ambignitatem + et si b c- b firi Z =0 si c = (b) sit Z=1 0+d si Zao fit p(d) si Et vicissim si zu efit c- b si Z unde Z = b (1) + 6) C si Z- 1 est c = 1b) Ergo n Z- 0 est p -1d) si Z = 1 est p = d et rursus =1 -Z.d +7d (b)C + (p)d An utiliter qursus ad hibe bitur D) = 1-Z, tud si p- d est Z = 1. Ergo ut ante Z fiebat ex C et b, ita nunc ex p at (d) Ergo fit Z= Cd) EP) + op. Hinc si ex ob c = b sit. p -(d) et ob c= (b) fit p= d, fiet jam Hine vicissim si Z = 0 est c-b invertendo si p = (d) est Z= 0 Ita tandem aequaio theorema aliquod conveniens sum assecutus. jam quia (p) = 1- p fiet b() dp + (d) - (d) p = Z seu dp + 1 + dx p d = Z seu p- Z d +:, 2d -1 seu p = Z-(d)3:, d - (d) sed d - cd) = d - 1 + d et (() = 1 - d fil Z+d - 1, :, 2d -1 = p vrl b(C) +1b)C = dp + (d) (B) sed praestat tamen prior prop imd si quaritur quantitus sit 0 si = b et quaesit 1 si c - (b) R. Erit b (C) +b)C = Z. Ihtiopes marum sequetu quod est in integris. Sedmoxsesso lvimus ergo sequentia ido to 4to V ... 90Zd conditionas niepps. invertu -- 2. g irit (BX) + bC 2 Erit (2) + Zd = X = (Zd) 2 Erit (Z)d +Ze B si exo 1:- c= 1 2 Euto (2) D) +Zd = p. hac novum et idiiu 1. e ..- D...... 1- Z- d sole fo ....... y. quanditas quae sito si c b et e si c b) fit lilcte t b e vg L. c. d. e 47dC y= deZ)de 2. X= Z (cd C) +(Z) d. C = Ze + (2C. d.e e .. ed irso M al be b DC i cons. pagi un valo em ipsius ii b c= b) = B) e b = H- dcito fuy -o A x = Y etxace nso q+ b+ d) + b7d + b) dte+ ad si c = (b) = d et 6 () d) sit P i b briu sibec conveniunt fini in (0 =4 + b) +b) d + + 1hl0 pyto eddempositosi ex 1 fit N - 1 Si C- sin. ixtie ave .-10 erit X 10 non queniunt frat re fit que 1= b01 1V) de Hb +6)0) (O= B seu fit q ea B, diC, ut ex b, C,t o = g + bdHb)d + et d firt shalibet 3 quoniunt fiet utige oy oo=q+ 2b te fit q20 Hu si cxb) et D ~osit y 20 et X =C quade in e b D21 fit Y= e et X ) stt (din B et d non conveniunt fit Iam supra si cab =d fit y = 0 et X = 1 o= 9 4b)+ e et sit q= e et HGdx Huc si b et E quenant est 9 - B. sin Hac methodo Poteris =Cadt e + esde) bet cnonquamm est que, ergo fit cb. (d) fit y = C et X= (C) Fy= a)e+ ()de pergi ad commuam in qua est r, et s res dignissima est quae producatur, si modo otium esset = (2) β + ZC posito B forman ex e, D, E, ut P est b,C, suporest ut quaeram a fi 3 plo quonaus 2 a 7 sit