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# Title: [Problema Austriacum Plus Ultra Quadratura Circuli] Problema Avstriacvm Plvs Vltra Qvadratvra Circvli (shelfmark Leibn. Marg. 230, Stück 1)
# Folio 37, page id 1815201908:0094
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# Model: FoNDUE-GD_v2_ft_Leibniz, run 74, 2026-09-06T16:05:13Z — 68 lines, status machine
# Lines: 68 recognised, mean confidence 0.78
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# After the first blank line: the recognised lines in reading order, one per line.

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LLLHETA
 R
Derectangulorum inter se propotone.
P E OPOSITTO LV
ABlinca; divilatuerir vecunque in C d B:
Dico AC B, C DB rectangula, aequalia esse rectangulis BD A,
DC. A.
Demonstra
dracis AC, CD, DB, unacum rectanss ACB, C. D B, bistuBEIS, e un
B A quadrarum aequaeur quadracis BD; CD. C A. Va CaM TCCAMOUHS BD A.
DCA bissumpeis: Igitur ablaris communibus quadracis AC, CD, DB; FEIMa-
nEnE ACB, C DB tectangulas xqualia rectansulis BD A3 DC R.
Corollarium.
DRopolitio hxec quoque rera et, Si AB linca; recumque de quorcumque punctis
dividatur. Eademque elt methodus progrediendi, d demonstrandi, qua in pro
Posicione rui lumus.
PR OPOSIII
2I Fuerit ve AB ad BO, Sic AD ad DF, _ BC linex equalIS L F.
d
DICOABDE, rectangulum x qualc esC rectangulo CBD.
Demonstr
Voniam per constructionem A
Lect, ve AB ad BC, SiC AD
ad DF, cric permucandos inver-
cendo, ve AD ad AB, sC DF ad F B, id est ad BC: X dividendo, ve AB ad
BD, SIC FF ad D E, id eA BC ad D E; quire ABD P rectansulum; aequalc
eA rectangulo C BD. Ouoderac demonstrandum.
Vadrarum AB, aequale es B A quadratO; sed A B a quadratum XQUAEIT a L. Sccun
LVI.
e LdEddetce Ldet
tuerie AB recta diuisa in C e D vE AC DB, linex sinE inter se
a quateo
Dico CD Guactatu; aesualt quactato C via Cu CCClaG
ABCD.
Demonstratio.
Vadracum AB,  C Guaatis AC, C B, bna cum ACB rectangulo
pC. ed HC quadracum, una cum reclatsalo A C b3 a quale cl re.
ctangulo