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# Title: [Problema Austriacum Plus Ultra Quadratura Circuli] Problema Avstriacvm Plvs Vltra Qvadratvra Circvli (shelfmark Leibn. Marg. 230, Stück 1)
# Folio 548, page id 1815201908:0605
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  1
eq ill sta
es
si
AIXPER BOL. A.
Constructio es demonstratio.
ACZ SE A recta quam ad diamerrum aacam BC hyperbola DCF, ordinarim
oporceae applicare: ponatur per praecedemem recta quaenis DO, ordinarim ad
arhuius. dracum ordinarim poliea TC, Ve seclansulum BRC ad ordinacim posiram in
CA TC quadratum ad A quadracu. OUac acz  RF; aequale cA A quadraco.
quia verO RP. aequidistae FC oramaUm POSITE, recta quoque RF. ordinacim ad
apencala cl. Pelecimus igicur quod poltulatur.
diamerrum BC: quae eidem occurrar in puncto I: e hac ve quadracum PC 3d qu’a-
dracui A ita BFC rectangulum ad BK C reCtanGUIU: XF PEF R PONACUF RF P2-
rallela TC. Dico illam lacistacere pericioni; es enim rectangulum BLC 2d qua
puncto R: Sed ex constructione vereerangulum BIC ad rectangulum BKC, ita
23. huiHI.
PROPOSITIO ZXV.
Porrear ex dato in diame.
ero hyverbola puncto
Ordinarim lineam applicare.
Constructio es demonstratio.
Acum Ccin diamerro AB, pun.
CTUI C, CX quO OPOFTCaEre.
cram ad camdem diametrum ordi.
natim applicare: ponatur quaeuis
b ordinacim DF, cui ex C aeguidi.
Aans dueaEur C F. PaTeE C F Cacis.
Facere peritioni.
PROPOSITTO ZZVI
Demon-
Nnis linca per verticem diamerri hyperbolx ducta, e ordinatim ad
eandem diametrum polica asusuals, secllotrem contingit.