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# Title: [Problema Austriacum Plus Ultra Quadratura Circuli] Problema Avstriacvm Plvs Vltra Qvadratvra Circvli (shelfmark Leibn. Marg. 230, Stück 1)
# Folio 637, page id 1815201908:0694
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# Model: FoNDUE-GD_v2_ft_Leibniz, run 74, 2026-09-06T16:05:13Z — 73 lines, status machine
# Lines: 73 recognised, mean confidence 0.84
# Machine transcription. Not an edition. Errors are expected: about 8% character error rate on Latin and French lines, higher on German.
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# After the first blank line: the recognised lines in reading order, one per line.

onttin
AD
AR
Xqual
eAe H
Perbol
de
daurer
lencin
lection
anluer.
iamett
fuera
lit
ilun
SiMo
F6.
16
seid
1uE
1c0
HIX P ER BOL A
Dico HC puncta esse ad eandem typerbolam cuius alimprori lune
AB, AD.
Demonstratio.
Voniam Cupponuneur linee F C,
LE F, F. II Candem concinuarera-
tionem, rectangula C+FTI. quadca-
coCD, adeoque e incer le aqualia
TunT: CA auTeM F, C+ ad R, C:; VE AB
est ad A F; igicE AB HI, rectangu-
la incer se quoquelune xqualia: cum
exiildem rationem habeane compoti-
eam, ex quibus ratio GF FI rectangu-
lorum componicur. puncta, sieux H H C. ad usperbotum lunc, cuius alymprori lune in
AB, AD.
PROPOSII
AABC, e ex puncto quouis D excra dusulum atumpro ducaneurre-
etx DF, occurtentes AB in F punctis. Fianc aurem DC mediae pro-
Portionales INFOF D F, DC.
Dico GC esse ad eandem hyperbolam cuius cenerum est D punctum
Demonstratio.
DOnatuE DFL aquidistans AB, et
FR, CI parallelae BC. quoniam
isicur in concinua sune proporrione
D F, DC, D P, crunc quoque in con-
cinua analosia R F, L C, FIC, hoc est
DR, DE, DHiigicurre D Tad DFI,
(id CAD R ad D 1) AC K F id cA HIB
2d IC: rectangula igitur b DFIB,
DFC xqualia lunE: quarc B C Cc puneta ad candem  hyperbolam cuius cen- versa +o.
ETUM D.
PROEOSII
AIrculus AB C dinisus diamCErO AC.
Lhabeac BDnormalirer ad AC consti-
cutas; producta vero C A, AAEVE AD C ad
AD C rectangulum, ira recrangului AF. C
ad A F C rectangulum, X RanCrecris BD
aequales ec paralleIX F. F 21IMII
Dico FF fore ad eandem hyperbolam
cuius diamerer est crantuerta AC.
Demonstratio.
Voniam ADC ad ADC, est ve quadrac
LDB ad DB quadrarums isicur eciam crit
AF. C ad AF C rectangulum, ve quadracum BD
ad BD, id est F F ad F L quadracum: iOieur F F
est dhyperbola, ad cuius diamerrum C A F. ordi-
nATII POLEX(UNE E F.
Mmmm
C
MOnsticuantur duae linex AB, BC formantes angulum quendam
du. hutue
a  EEa