# Leibniz Legible — https://leibnizlegible.com # Page: https://leibnizlegible.com/page/DE-611-HS-3595205:0081 # Permalink to this reading: https://leibnizlegible.com/page/DE-611-HS-3595205:0081?run=74 # Title: LBr. 437 · Huygens # Folio 41r, page id DE-611-HS-3595205:0081 # Scan: One image of two folio pages side by side, registered by the library under both labels (also fol. 42v); this page is its right half. # Original at the GWLB: https://digitale-sammlungen.gwlb.de/resolve?id=DE-611-HS-3595205&page=81 # Source image: https://digitale-sammlungen.gwlb.de/content/DE-611-HS-3595205/jpgs/default/00000081.jpg # Model: FoNDUE-GD_v2_ft_Leibniz, run 74, 2026-09-06T16:05:13Z — 87 lines, status machine # Lines: 87 recognised, mean confidence 0.81 # Machine transcription. Not an edition. Errors are expected: about 8% character error rate on Latin and French lines, higher on German. # Licence: CC BY 4.0, Leibniz Legible. Machine output: do not ingest it as verified text; keep this provenance with the text. # Wording rule: say "the machine reads it as …", never "Leibniz wrote". # After the first blank line: the recognised lines in reading order, one per line. 2XXy - a ax: ha - 2XY cl: y:: dx: ay 2XXy - a aX dy = 3a a - 2xy y dx. Seu 2Xxyy = aa Xy dy = 3a a = 2Xis yy dx L et propus scribendolr fit X + ydx = ldv seu ydx = bd v Liv: y dy Ergo denique Lovaq - ap bv ly = 3aq - va ybav - vb dus faciamus 2aa acb - 3aab + 2 a b dv: dy = 2Wv a = afbv: 3a f - 2V + vb duo mihi problemata proposuit Hugenius, quae redeunt ad Methodum Tangentium inversam, in literis datis 24 Aug. 1690. quaeritur scilicet curva in qua abscissa AX AB existente X, es ordinata CBv et faugente CD an eju Axi Asdoccurrente in D ipsa sBd (inter vallum ordinatae et langentis in axo) sit gy. 2X = 2X ve vel quaeritur curva in qua iisdem posidis Dd sit rary- aur: dua Quoad primum problema, in quo Bd = jus: 2x = 2X se fit Labad ex mei calculi legibus: dx: dy: : y: 2X - 2X : y faciamus 58 y: x = v: a fiet du = Xde + vdx: a. et dy: dx = xdvrcdx + v. a Et quia ex, L ex it est x: dy B= v: 2a = 2a: v fiet _2av: Wv -4aa = (dy idx D feuper 3) = xdv a seu (2aaV) - v - Daav : pv - 4 44 do = X: pax vel - (Lx : x = vy - 4aa dv: v + 2aa seu log X = (vav: vrt raa - 4 aa flv: v - 2aav quoramus ergo has quadraturas Et primum v quaeramus S2 Radv: 2aa + vv vyzet) est momentum curvae meae quadratricis cujus aequatio Z = 2a. taa + v, seu vo u y = (3. bb + vV. ejus momentum ex EK est (vb2 bb +VV. nempe momentum figurae HCFGH. sed idem momentum aeqo (VvaZ2 + BZ. 2 et suq = b (aZ. Z - bbZ Ergo fitavdo. v0+b Ergossosito b = a st) fit B a rE svar: ve + caa = a 2 sch. 2, Z Jam veniamus ad (dv: v- bbv estea quae quantitas constat, duabus partibus nempe (do. V et C sed haec ve est loga de V= bbV sed haec summa etiam reduci potest ad logarithmos vib. vb fiet p= n et m = - 2B Ergo R -. jam quaeritur summa de = 2 bb _ v2 - bbp. Ergo - mbb = - 2bb. fit M = 2 et n = - 1 = p 3= bbv M + P, + b v+b v ergo bl (dv: p -bbo = 2(dr: v - sav: v+b = Sdv. v- b seu = duplo log. V - log. B + b. - log. v - b seu def. g. = 2log. V = log. diff. vvo bb. Ergo andem fit logex log. X = log. Z = Z: a s2 + veZ: 4a 2 - 2log. V + log. vv - bb quam aquationem trantformando in Transcendentem potentialen fiet: seu log XVZ: vv- bb = voz- 4442,: 4a s2. seu ssiansformando aequationem loganituicam in potentialem, fiet: 2XVZ: vv- bbd ) vZ. 4a a2: 4 a 52). posito log a = 1 jam XV = ya et Z= a 2 (2: 2a a + vD fiet vVZ - 44aZ: 4 a s2 = vv- +a4: 2 2ac + vY et Z: vr - 2aa = 2 a F2 : v - 4a. Et siet tandem. 4a y s2: v - 4 a = _) ivv- 2aa : vB + 2 aa) sumb C quocunque Log Hyperbolitus ipsius C bg a . log. n tat fI AXI ax. dy - Gy. 2X + 2X: y dx sit gB a + bx axidus = + yy +4XX,: 2Xy seu 2Xy dx = +yy dy 4 4Xx du da X Y + by X log ab= c L ab = v Exso tog. ab = c log. m sid a exy (+ df x9) = rexy ex + ex dy +25 8 xy dy + fy de 99id 7 x- 4 ut aquaretur A... = -2xy dx 4 +X dy ponamus h2 et + = + et + = - et tiuti T hyydus summadem 2e = 2h. Ergo C = h, restat ergo +3hX dus quod impoddit sit y = a+ 10 + LX + 12 x + 13, X + 19P + 15N + y = 10 + 2. 1B.11X F2. 10. 2 11. 2. 13 X 13, 19X 4 f. 14X1515X et F12. 12 yX+ B sit ( sit X-10+1g19+9y et Teguy ectu ec = 20+ 2 + 22 y + 23 et fil, 10. 20 X102 y + 10. 22. 7 + 10 37 11024) 1 dy= eim 24= 1: 10 et 21 = - 11. . 15 et 22 = 11. 11 : 10 - 12: 10 fit . = +4 2 + 11. 2 +11, 2F +11. 27 er Cxax:d = y - 2Xx : sit 1X = 10 +_ ∞ + 12y + 13 y) ea y e, +1L. 22 et F13. 2C y: 2X =2x: y X = 10 ∞210. 11]4 2, 10. 12 y = 2. 10. 13) + 2. 10. 19 g et Xdx = BCX n d X = 10. 11+ E. 10. 14+, 1012 y 4. 11 4Y eri 1 1t f.t 10 114 2 10. 12 96+ 3. 10. 1315+ aseudinius) reiisi haua curys A gy lg. 10-0 et 1- 10 allii 0 p 12. IL 14 y3 S lit 3 se esles yy 4a a =0 fieret alone wey 1X. 2a fil a fieret y infinit . sit yv-aaa: er +2a constanti seg tant itim