# Leibniz Legible — https://leibnizlegible.com # Page: https://leibnizlegible.com/page/DE-611-HS-861255:0096 # Permalink to this reading: https://leibnizlegible.com/page/DE-611-HS-861255:0096?run=74 # Title: LBr. 705 · Overbeck # Folio 48v, page id DE-611-HS-861255:0096 # Scan: One image of two folio pages side by side, registered by the library under both labels (also fol. 49r); this page is its left half. # Original at the GWLB: https://digitale-sammlungen.gwlb.de/resolve?id=DE-611-HS-861255&page=96 # Source image: https://digitale-sammlungen.gwlb.de/content/DE-611-HS-861255/jpgs/default/00000096.jpg # Model: FoNDUE-GD_v2_ft_Leibniz, run 74, 2026-09-06T16:05:13Z — 29 lines, status machine # Lines: 29 recognised, mean confidence 0.94 # Machine transcription. Not an edition. Errors are expected: about 8% character error rate on Latin and French lines, higher on German. # Licence: CC BY 4.0, Leibniz Legible. Machine output: do not ingest it as verified text; keep this provenance with the text. # Wording rule: say "the machine reads it as …", never "Leibniz wrote". # After the first blank line: the recognised lines in reading order, one per line. Si potentiae numaeri cujuscunque continue dividantur per numerum aliquem constantem C erit periodus pesiduorum. quia cum residui sunt divisore minores, ved tandeo sunt numero finiti, atque adeo redire aliquis priorum debet. Quo semel redeunte, redeunt priores. Hoc patet manifeste si numerus D consiveretur ut rhozalis, adeoque ejus potem tia quaevis exprimatur per 1000000, etc Ostensum etiam est alibi periodum semper rursus incisdere ab finc sequitur posito numerum n- 1 esse verbi gratia g, quem- a residuo 1. vis numdrum datum C, posse exacte diidere ipsum 99ggu et c. satis eValiquem posse dividi per datum C, et C cen jorem ipso, V-1, imo esse minorem si non sit prumptivus seu n seu C et n - 1 sint primi interse sequitur etiam si C et 9 la 1) etc secundum Thizadicationem ipsius n, seu quod idem est sficientem summam continuam potentiarum ipsius _ aliquam, posse HI posse dividi per numeri dati ni cujuscunque posse exacte dividi per numerum datum e, modo n et c sint primi inter se taec ero aequatio, n - 1 = qua ic tr solvi potest in integus quicuno sint integri n et sit primitivus erit e= minor quam p- 1 et e semper erit minorquam B quod si 0-1 - C D non sit primitivus erit tanc