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# Title: LBr. 454 · Augustin Thomas à S.Josepho
# Folio 33r, page id DE-611-HS-957479:0065
# Scan: One image of two folio pages side by side, registered by the library under both labels (also fol. 34v); this page is its right half.
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# Model: FoNDUE-GD_v2_ft_Leibniz, run 82, 2026-09-09T18:17:48Z — 51 lines, status machine
# Lines: 51 recognised, mean confidence 0.80
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X
ha = 37 sit X = 
ca
n et Z =q, fiet
X
3 a
 = 3P = 4q. sit seu narr + 3popX = nogu. sunt autem q et Y item hat p
primi inter se. Ergo ap est divisibilis por rr. sit r = st : a et RP R = 55V. et
 = Et W: aa fiet np = ssUvi: a, et dividendo per np: = vd: aa et
fiet np L pp aann + 3aa pp = viqqe, seu Siv +3F uw = aa vuqque
quia n et p sunt primi inter se, ideo etiam sat F, item V et Wd sut primi interse
sunt 5v et bo. t quia g et Y sunt primi inter se, etiam q et s+
sunt primi inter se. Ergo necesse est esse v= a, et W = a et fiet
seu 4 3t = aaqqu - S seu 3F = aq + 55, ag - 55
sit aq - 5s = H seu aq = H+ ss et a9 = 3tt -55, fi. t _ 2 tt = 255
5+ 3t4 = aag9
seu H = 55 et aq = 255 7 quod ettam statim  duci poterat
ex squatione 5++ 3 3t = aagque, nam posito S=t, fit 45 = aagq
sed hac quoque non licet, quia ita su et to non essent primi inter se
Ergo redeun Negecta tamen hac suppositione fieret n = p et X =1
et y = ag: Y, et 9 = 255: a et Y =55: a et q. Y = y: a = 2
ut olem. Redeamus jam ad 3 = aq +55, a9. 55. Et videamus
an aliquis valor ipsius T divisor posit esse at aq - 55 erit aq = af +ss
a
et fiet  af + 255 = 38: af, sen  255 = 3t af =as
ergo nisiet sit eliam quadrato quadratus, habebunt L: af, et =af,
divisorem communem cum f, ergo 255 habebit etiam communem divisorem
Cum f, ideo set t non forent primi inter se. Ergo  sit t = Z
fiet a3f = co, et H = 3ad: co = af seu 2aa55 = - 7 - cd
t
72
22
bon
 2aas= 2Z = 7h- eo, seu 2a5 +ZZ, as
seu 2, a5+72. a5- ZZ = ZGo, cele y7 + c0co, 7 + Cd, 7- c
fieret as = 222- c0co et 205 v al 22
L
A esset a5 - Z2 = 27 - cos
et 225 +277 = ZZ + coco seu 2a5 = ZZ- 0Wd = 47Z 0 Co seu 327=coc0
quod non licet vel 2a52Z = 77 - coco, seu 2a5 = 37Z -coco, et
e
a5+ZZ = 7q + colo seu a5 = coco, et 2colo = 372 = coc seu 2 = cs
quod nohimus. vel a5+ 7Z = (e: a) (ZZ + coc0) 11 2a5 - 2Z7 = a (2Z- c010)
fiet a 5 = (C- a, : a) ZZ + (C: a) coW = C) (Z con) + Z3
(a+2C,: 4) ZZ = (a: 20) Coo ven aZ + E cod
 28 ad = Z2R. loco,: 22F coro
Z
de
2
a colo
re