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# Piece: https://leibnizlegible.com/api/records/1064/text
# Catalogue record: 1064 — [Aufz. zu Differentialgleichungen]
# Incipit: q ad 1 ut dx ad d, [dy:dc]
# Date: 1676
# Record in the Leibniz-Katalog: https://leibniz-katalog.bbaw.de/de/extended-search?id=1064&katnr=58614
# Work: https://leibnizlegible.com/work/00068056
# Title: Leibniz-Handschriften zur Mathematik LH 35, 6, 11
# Folios: Bl. 9 (from the shelfmark LH 35, 6, 11 Bl. 9): 2 pages, canvases 17–18, page ids 00068056:0017 to 00068056:0018
# Original at the GWLB: https://digitale-sammlungen.gwlb.de/resolve?id=00068056&page=17
# Lines: 21 recognised on 2 of 2 pages, mean confidence 0.83
# Catalogue: Leibniz-Katalog / Arbeitskatalog der Leibniz-Edition (https://leibniz-katalog.bbaw.de/), ed. Arbeitsstelle Potsdam I der Berlin-Brandenburgischen Akademie der Wissenschaften, CC BY 4.0.
# Machine transcription. Not an edition. Errors are expected: about 8% character error rate on Latin and French lines, higher on German.
# Licence: CC BY 4.0, Leibniz Legible. Machine output: do not ingest it as verified text; keep this provenance with the text.
# Wording rule: say "the machine reads it as …", never "Leibniz wrote".
# After the first blank line, page by page: a "## Folio <label> — <page id>" line ("## Canvas <n>" where no folio label is recorded), "# " lines naming its source image and model, then its recognised lines in reading order, one per line.

## Folio 9r — 00068056:0017
# Source image: https://digitale-sammlungen.gwlb.de/content/00068056/jpgs/default/00000017.jpg
# Model: FoNDUE-GD_v2_ft_Leibniz, run 73, 2026-08-27T15:28:38Z — 11 lines, status machine
q ad l ut dx ad d, dusidc
ad 1ut dx ad de ddy - dyddc,: dede
 ade 9. de day-dy adc = dx de
si g= c n ddc = 0 fiet utas
 Cde Cddus = dx de
_ dx ddx + dyddus = ddC =0
= SSdxax+ dydus  dx
:l
et summando
eCaus
de dx = cdx = 0

## Folio 9v — 00068056:0018
# Source image: https://digitale-sammlungen.gwlb.de/content/00068056/jpgs/default/00000018.jpg
# Model: FoNDUE-GD_v2_ft_Leibniz, run 73, 2026-08-27T15:28:38Z — 10 lines, status machine
gd0) = C (ydc) = X dy: dx de
C dy = c d Xdy. dx
yax-dy = tdc = c dy - c dt
x C = +de) dy- dt
dC = Fddc + de dF
ce
dy- at si dy- at sit constans
seu si ddus = ddt ou bi aut si du
aut si du - xdy: dx constans aut
si ddus = x ddy: dx +dy