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# Piece: https://leibnizlegible.com/api/records/52474/text
# Catalogue record: 52474 — für [Th. Schöttel]: [Rechenaufgabe mit Lösung]
# Incipit: Titius soll Cajo eine gewiße Zahl als b Kreuzer geben,
# Date: 1714-02-19
# Sender: Leibniz — Addressee: Schöttel, Th.
# Record in the Leibniz-Katalog: https://leibniz-katalog.bbaw.de/de/extended-search?id=52474&katnr=23828
# The Leibniz-Archiv's transcriptions of the letters of 1714 (pre-edition): https://www.gwlb.de/leibniz/digitale-ressourcen/repositorium-des-leibniz-archivs/laa-transkriptionen-1714
# Work: https://leibnizlegible.com/work/DE-611-HS-867168
# Title: L Br. 827 · Schöttel, Th.
# Folios: Bl. 49 (from the shelfmark LBr 827 Bl. 49): 2 pages, canvases 97–98, page ids DE-611-HS-867168:0097 to DE-611-HS-867168:0098
# Original at the GWLB: https://digitale-sammlungen.gwlb.de/resolve?id=DE-611-HS-867168&page=97
# Lines: 69 recognised on 2 of 2 pages, mean confidence 0.75
# Catalogue: Leibniz-Katalog / Arbeitskatalog der Leibniz-Edition (https://leibniz-katalog.bbaw.de/), ed. Arbeitsstelle Potsdam I der Berlin-Brandenburgischen Akademie der Wissenschaften, CC BY 4.0.
# Machine transcription. Not an edition. Errors are expected: about 8% character error rate on Latin and French lines, higher on German.
# Licence: CC BY 4.0, Leibniz Legible. Machine output: do not ingest it as verified text; keep this provenance with the text.
# Wording rule: say "the machine reads it as …", never "Leibniz wrote".
# After the first blank line, page by page: a "## Folio <label> — <page id>" line ("## Canvas <n>" where no folio label is recorded), "# " lines naming its source image and model, then its recognised lines in reading order, one per line.

## Folio 49r — DE-611-HS-867168:0097
# Source image: https://digitale-sammlungen.gwlb.de/content/DE-611-HS-867168/jpgs/default/00000097.jpg
# Model: FoNDUE-GD_v2_ft_Leibniz, run 79, 2026-09-07T03:33:42Z — 34 lines, status machine
rlgtciss 
sitips vel Cajs ah ene gecaeißte tast
nec  avengis geb, Titius at abre sat inste
ale Sirbenzigua, und Cajus nicsto aer VU,
lits
Khagt sih wic viel  diebenzehnre eas
gebi und aietieb Scebonra Capis
humingeba solle
b = 17m = 7n. odr b + 7n = 17M
man devidir. b mit 17 imud b + in = m
b = 17C +d, irid c + d +7 = m odr
M - C = p.
must man doro engus sien ninc zahl n Weli
mit Z multipliciet or und dac product
mit d vramesort, mit e7 aufgehe. Dieste zase
ar. sonnan mehr  viale dienn, abrr
man sucht die Meinaste n,
d +7n- = 17P odr 7n = 17p - d
p 17 17 = 2.7 +3 Ergo s evid
+2. 7p + 3p  -d
odm R = 2P +
M= aY-ad
r-d
su 2 ∞7 Y 5d
∞ = d M= 17Y - 5d+C
2
2B -d = 9, fit 3p - d = 79, 
jam 7= 2. 3 + 1 et fiet
p - d = 2.39 +g et fiet p = 29+
qo
q+d = Y seu 4 = 3Y - d p = r. 2d 3
Man d drgestalt haben io
us
solgende solution

## Folio 49v — DE-611-HS-867168:0098
# Source image: https://digitale-sammlungen.gwlb.de/content/DE-611-HS-867168/jpgs/default/00000098.jpg
# Model: FoNDUE-GD_v2_ft_Leibniz, run 79, 2026-09-07T03:33:42Z — 35 lines, status machine
c.
tir degaben lase
duc quotio  CsA
b dividiae man
uut 17 (beabt abrqu d.
venn nesma may
dic nacsst zase ubque D est sis unt 2 grrad dividum
uad ers ging alc
cassit, und nenuo dae, de sic. t.6 thril Y,
si rrund Titius gbu sbllas 17Y - 5d +C, reben
gehare, und (ajus Zurmkgebu 17Y-
d Scebrum
desest man stlle mahn 100. b. ait  d erben zesue
wenigre sirbenn
1550
t
d  CF5 
d = 15
420 P=5 R= 10
BI = 10 1017 - 10.
v
b 10 b = 17m- VK = n
b-
getf 17 = 2.3 +3, fiet  + = =
seu C M, SM =e- 2+n = p.
+ 3 m
ciL
A
f_ 5. 3m = 25 seu f - 3M = 2. 35 +5 seu
F-s
2(+ m = + seu f - (= 3l. seu f. = f- 3
Sit b = 100 fit 07  b= 14. 7 +2 fit C = 19
sit F1 fit s = - 1 M = c+2 = 3 n = 1014 +6
n = -9
F9.7=