Leibniz-Handschriften zur Mathematik LH 35, 6, 11, fol. 10r
Machine transcription. Not an edition. Errors are expected: about 8% character error rate on Latin and French lines, higher on German. Mean line confidence on this page: 0.78.
Original at the GWLB · Page image · Annotations (IIIF) · Download text
The machine reads it as
- Examinemus Calculo solationem problematis de figura in quam
- c
- se pondere proprio carvat funis.
- S
- Ca veccece
- ranscementem dy=aax: Exx-aa
- 2
- Invenimas autem Aequationem
- Aequatio autem praestanda est
- y Sax +du: (Nax +dus = y - X dy: dx.
- seu fiet.
- Fyraxrdu (Sapidus V- (sax tau el der dx
- X dy: ax
- en (y Faxadus) (Fax edis dyst y dxray) - udx +ay X dy: dx(= ssatus dus son. dus
- a
- jatum ayx per I est dy: dx = a: 1XX - aa. adeoque fiet
- e
- seu vax nau dy. dx = =Sranaau d ay. dx
- 4x
- d dy: dx = axdx: _ (.2) Xx- aa adeoque per . , ex A~9. 5 peretu
- co = (-1.2 Cd dc) fit EF +a a: SXK aa = = XadX. XX- aa ExK-aa seu
- 1.2
- 23: 2
- sit C0 = Xx - aa. de
- fiet d 1.rxa na
- sex aa d
- e
- et a a: LXX= aa
- red
- ap
- sublato communi divissre irnationali fit. ( sit Hrixa
- = = (, 2 2 a X AX: XX. 04 Yer aa
- ex +que = X dx: XX- aa. Adeoque Ax idy dx. Xx. ( nr a
- seu 1 + dy idr = XX: PI xX a4
- seu 1 + aa. XKG XX. 1 XX aa.
- seu 1 + aa: xx aa = XX. B( ex aa
- C
- ergo subest error inralculo
- eu XX aa +aa XX
- XX aa P) XX aa
- Vdx + du a: (XX -aa = - ( Sax +du a XaX: XX - aa 1XY-aa seu divisione facta
- L (10)
- adeoque er aequ. 5. ex n 6 et 7. fit:
- eu Yax +dy - x (Sdx +du X: Ex aa. sive Sit dy. de =- sot lyX. n a
- lesen pro du: ax ponendovalorem ex aeq. 6 fit 1+ dy: du = X: rxx- aa. Ergo ex 10 et I1 fiet
- (11)
- 1=-Fax +dg: sex aa seu Exx aa _-Ssaxraus. cujus differen
- 1
- tialis est: Dx dx : Ixx -aa = - Sdx + dus seu XXdx: XX aa = dx + dy. seu
- (14)
- XX: XX =aa = 1 + du: dx quod succedit test enim ipsissima aequatio 11
- (16)
- Itaque habemus solutionem desiteratam
- si velimus a dx: exx-aa invenire rationaliter sic licebit procedere. Sumatur
- XX aa = (X ZXC DC00 et X = co:2 + aa: 2C0. fit adeoque YXX- aa = X
- Ergo isiet denique
- dx = deo: 2 - aa dco: 20000 sen =coco- aa . ticoco
- A dx aa: YxK- aa = cocoto coco -aa duo: 2c0co aa: aa = 4c000: 10 =- d0 : o
- +aa: 2C0 W: L= aa loco: rd
- Ergosetdentr
- quae pendet ex quadratura hyperbolae. Itaque problema est solutum. Nam
- qdordinatae hujus curvae ad tangentem verticis su basius, sunt lagarithmi ipsarum co
- 1 L
- paxem
- seu ipsarum X = Xxaaa posito X ese abscissas seu AB
Cite
Leibniz-Handschriften zur Mathematik LH 35, 6, 11, fol. 10r. Machine transcription, not an edition: Leibniz Legible (model FoNDUE-GD_v2_ft_Leibniz, run 73). https://leibnizlegible.com/page/00068056:0019?run=73