Leibniz-Handschriften zur Mathematik LH 35, 13, 1, fol. 88v
Machine transcription. Not an edition. Errors are expected: about 8% character error rate on Latin and French lines, higher on German. Mean line confidence on this page: 0.80.
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One image of two folio pages side by side, registered by the library under both labels (also fol. 89r); this page is its left half.
The machine reads it as
- Esto aequatio data dy: x = XX + gy,: aa, seu
- (2)
- i3 qaadys +v agdy =d
- vi 12, 10, 11 suyt
- fet ly :dx= 22aa + Elayt 20gy,:, tiaa F quay ~ 2XX +9y,: aa, et habebimus aequationem
- tr. 22a F, 2103y +u2oaayy
- 20
- in auxx+ qa xy 4 aayys + 28 ay3
- vidermus an hic utiliter liceat facere 4) = 11. mar. X1 7X
- etfiei 12, 1. 21 a = 11. 20ay + 10.40 yy 120
- 10. H ay
- dA. D + ac du +dH 20 aydx + 102gt ydx + 1. 2onady + 10. qu.ydy 0
- Hanc aeq. 7. differentiando, siet:
- U d21 aa do 11 d2o dy dx
- 2.1X(12 20 dx A. Et ay ex
- 12Xx dqudx 10 dal ay ax
- ut (80
- 10 d4o gylx 10 4 adus
- (ullistinti uite e
- eu rindeltiglicata per 60 addita aeg. 2ib
- Edinoutst 1 nabru 4 100 obyaue 2240
- 00. 6oyydx -00.60 aadu
- fier 40F0 sed ita etiam frertet 6020
- quid qun biecto itaque vereor, ut liceat tollere temminum absolutum in aeu5. Eo ergo retento
- 00. 60 XXdx +
- duc du. 21 cayax L dureang X tdlo. 40 ydx + 11. 21 a dy 7 H. 20n ay dy , 10. 40 agy dis
- si differentiamus fiet
- pde Ta du
- d
- Bx
- Udro
- 12 d.. B2XX 140
- a10 4
- 101a
- 10d4d
- 12 4 eb 2. 10. 41 aaydy
- 140. axedy
- comparandum crum aequ. 1. multii l. per 609+61a
- bi axplx + bxpydx + biagydu + 60 2 dx -6qa dus - 6causny ce
- b=0
- iat
- fet b2 2. 10 =29 et ex dy fit 2. 1941, 11. 20 = 60, seu 41- 20 4 60
- ex joste
- Ex gydx fit d40 = (2) 20 + 41 (-20) Ex y, d28 7 d 4) 1)2. 21
- d11 =0
- 1
- denius ex ex sit d21 + 2X 2. 40X =+ X d qu 2.20 + 4, - 20, antitti potest aequatio hac
- ultrum qoia sola continet 22 item ag. prim ex is 12, quia sola continet d4
- Porro ob sublatum terminum altonum in aeg. 5 Z2= AIXX: aa Ergo ex aeg. 1+ faet
- d21. F 2. 40X + XX d40= - 2. axX + 41 - 20 Res ergo redit ad, ce gy. 12. 13, 16
- seu 2072521 - 4
- d2L ex aeq. 16, d21 + 4sset 4. X() 21 + XX2(2 - - 2. 4 1XX + 41 - 2 s21 + 41 - si Aad per ta set +. EF sat = L XF L a1X + a - 2( it + 41, et differtulando fer.
- ponamus 21 esse cognitam pro arbirio assumendam Ex 13 fiet 20+ 41= 2521 Ergo
- res redit ad aeqqu. 12) 16, 17. Eit ex 12 fiet d40 = 2 sel Et 40 = 2 s521. superest
- et habeber I, atque adeo cum 21 pro arbitio assumi possit habetur quaesitum sea quaesita 4I
- la
- potest poni 21 constans adeoque (21 = 21x et B2 = 2. U XX
- Assumitur alia differentialis ANX A- 4 1xax + 2 a ydx + 20 y ux + N aatus + 40 a y dy = (2) = 0. Et fiet
- ex 1; - d g: dx = XXF yy, : - aa = (per 2) - MIXX + 21ay + 20yy, :, 4aa + 4ugy unde prodit aequatio
- +40xxA + 41 ay + 40 yy = (4) =0
- F 41 ad XX) + 4 cl Xxy + 41 A yy + 40y3. 720 vel +ila + 20 ad
- = AI a XX )+ 21 aay + 20 a gy
- unde differentiqudo fit 2 4 Xdx + d H ay. + d to yy rodau
- ago XXx +d 20 ayx
- Haec aequatio coincidetur datae, multiplicatae perbo,
- cui addatur assumta 2, multi plicata per b, sart
- arlaaix
- 60 xxdx
- .
- + 60 gydx -b aadus
- 7 = (9 =0
- et fiet .. ...
- ∞ AIb xxdx +2by dx + 20b yyax +alabays +40 b ydy s
- Iustituta jam cincidentiatione t ob ydu, sit b = 2. Et ob du fit (2)+ 20 = - 60 (+2) 41 Erit 60 = 4 2(7) = 41 - 20
- vyarex
- ob yydx fit 440 = 60 +2. 20 seu dgo = 41 - 20 +2. 20 seu d90 = 4- (8) 41 + 20 bC f
- Ax
- ob ydx fit d4l + d20 = 2 t (9) = 2. 21 denique ob dxx fit 2. +oX + ex d G0XX + d2 I = 1) ( 1 - 2C) XX. s
- redit ad solvendas aequationes 8, 9, 10. Sit 2 quantitas constans, seu d21 = (11) = 0, f. eth
- Et ex 9 fier 41 +20 = K (12) = 2(21. Ergo Ex 8 fit 440 seu A 25i1 et 40 (14) = 2s21. quibus
- valoribus ex 11, 13, 14 substitutis in aeg. 10, fiet 2421 + 2XX21 = = 41∞ 2OXX - 2. 4 1XX) -20xp - 21xx
- andesit 2X (21 + 2XX) 21 - - 2XX s21 =0 seu B21 + 2Xs21 = d seu (s21) = (2) 521 + 2 1X seu 21+ 2 21 dx + 2X d20
- Ad qua 221 =0, hoc non licet, hisi sit 21 = 0. Hoc pacto ex aeq.q fiet d41 +d20 = (17) =0 Et 41 +20 = (18) =c
- Ergo et d40 9) = C et 40 = (20) = CX sed ita ex aeq. 10 fiet 2E XX + CXX = (- 41+ 20) = Z Cxx, quod
- est atsurdum Ergo nonlicet facere 21 constantem nempe 41 et 20, non constituunt nisi unam quantitatem 21 + 20
- itaque in aeq. 10 fiet (2 + 2521 + d21 = - X∞ C 2Xs21. seu 2X (s21 + aex se1 + d210 seu
- 25
- et posito 131. fiet s21 = dg et 21 = ddgu, et d 21 = d3’g, et fiit 29X + 4XX d + d38 = 0.
- si esset d3g d’ =0 fimet 2X = - 2d8 seu log X = logi
- ex est conlans non potest ’esse constans, C non litel faicere 2ca = - 41XX ad deprimend a, ey.C
- et d = dv et d(() = b lv. et ddlo - b dv acv b
- A 8- V Bo sia d log f ag L hg bts v et a V- vB s = do b + dtotr b + de dso. lul epupuirbid qu nus sen foe tile prio sim letepes ater
Cite
Leibniz-Handschriften zur Mathematik LH 35, 13, 1, fol. 88v. Machine transcription, not an edition: Leibniz Legible (model FoNDUE-GD_v2_ft_Leibniz, run 74). https://leibnizlegible.com/page/00068196:0174?run=74