[Problema Austriacum Plus Ultra Quadratura Circuli] Problema Avstriacvm Plvs Vltra Qvadratvra Circvli, fol. 1084
Machine transcription. Not an edition. Errors are expected: about 8% character error rate on Latin and French lines, higher on German. Mean line confidence on this page: 0.90.
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The machine reads it as
- CBAOIDES HSEERBOLTOYM.
- EKOTOSIIIO CEXXZIN.
- Mnestectiones cemens ls perbolici axi aquidistantes, (i inter se
- quoquexequidistene, cenera habene in linea qux à cenero hyperbo-
- lx per axem conoidis producte, normalis ad parallela hyperbolarum
- Plana ducieur.
- Demonstratio.
- Tcigitur planum ABC per axem conoi-
- deosinclusi cono D R F alymprorico, od
- quod aliud ponaene B CFT ad rectos ansU-
- Jos, quod aequidister axi conoideos. Dien
- sectionis B GFT cencrum eAe in P. I, quX a
- ceriero hrperbolae AB C ducirur normalis
- ad planum BCTI. planum enim BC.HI.
- productum lecer conum, e exhibeat hy-
- perbolati RGF; huius centrum erir in
- recta FI. Acqui hyperbola PCrTI, ijidem
- asempeocis claudirue quibus hyperbola
- R GL, VEPATCE CK 176. ex 177. huIUS. ergO&
- cenerum cum ca habee commune in recta
- E I. Similicer ostendam omnes hyperbolas
- ipsi BCFFT parallelas habere cenerum in re-
- eta PI. LiguEFerBO prOPOSiTUM.
- PROPOSITIO CLZZZV.
- Ececur conoides hyperbolicu ABC.
- lectione per axem _ altera BDF,
- qua recta (IEad planU pCFAXCI, CON-
- curracque cum laceribus crianguli per
- axem COnIA(YM PEOTICI CKETA CONUIM.
- Dico secrionem B DF. ese hyper-
- bolam que cum lectione coni FDC,
- non concurret, qua in eodem plano
- exictic.
- Demonstratio.
- CM CK 19. PI. _ CICHHIC. 3. TI. PALCE R FV
- LBA L, aCDE C rectis L. M, PL
- Voniam planum BDP. rectum est ad
- INUM PCF EXCM AB C, _ concurrit
- cum laceribus criansuli peF aXCMI CXEra CO-
- num, isicur sectio FDO coni HIMOL.
- hyperbola est, CUIUS CCHErUM SIPPONACUE
- punctum P. ex quo a (yMPEOTOS dUCATUEPO.
- Dohcaigitur diametro P D, aNumproque in
- ea puncto quonis R crissAnEuE R S. D, 7 que
- Eine normales ad planum crianguli ABC
- peraxem, ex secundum R S, DO lectiones
- hancbasi conoidis parallela, exhribebunc hae
- sectiones circulosOTV, AF C _ ZV X
- 1064
Cite
[Problema Austriacum Plus Ultra Quadratura Circuli] Problema Avstriacvm Plvs Vltra Qvadratvra Circvli, fol. 1084. Machine transcription, not an edition: Leibniz Legible (model FoNDUE-GD_v2_ft_Leibniz, run 74). https://leibnizlegible.com/page/1815201908:1141?run=74